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balandron [24]
3 years ago
7

A glucose solution that is prepared for a patient should have a concentration of 180 g/L. A nurse has 18 g of glucose. How

Chemistry
1 answer:
Irina-Kira [14]3 years ago
6 0
<h3>Answer:</h3>

0.10 L

<h3>Explanation:</h3>

The concentration of glucose  is given as 180 g/L

The mass of glucose is 18 g

  • Concentration in g/L is calculated by dividing mass of the solute by the volume of the solution.
  • When calculating molarity on the other hand, we divide number of moles of the solute by the volume  of the solution.
  • Concentration in g/L = Mass of solute ÷ Volume

Rearranging the formula,

Volume = Mass of the solute ÷ concentration

             = 18 g ÷ 180 g/L

            = 0.10 L

Therefore, volume of water is 0.10 L

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Balancing the reaction by oxidation number method k2cr2o7+sncl2+hcl​
Mumz [18]

Answer:

K_2Cr_2O_7 (aq) + 14 HCl (aq) + 3 SnCl_2 (aq)\rightarrow 2 CrCl_3 (aq) + 7 H_2O (l) + 3 SnCl_4 (aq) + 2 KCl (aq)

Explanation:

The products of this reaction are given by:

K_2Cr_2O_7 (aq) + SnCl_2 (aq) + HCl (aq)\rightarrow KCl (aq) + SnCl_4 (aq) + CrCl_3 (aq) + H_2O (l)

Firstly, dichromate anion becomes chromium(III) cation, let's write this change:

Cr_2O_7^{2-} (aq)\rightarrow Cr^{3+} (aq)

The following steps should be taken:

  • balance the main element, chromium: multiply the right side by 2 to get 2 chromium species on both side:

Cr_2O_7^{2-} (aq)\rightarrow 2 Cr^{3+} (aq)

  • balance oxygen atoms by adding 7 water molecules on the right:

Cr_2O_7^{2-} (aq)\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)

  • balance the hydrogen atoms by adding 14 protons on the left:

Cr_2O_7^{2-} (aq) + 14 H^+ (aq)\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)

  • balance the charge (the total net charge on the left is 12+, on the right we have 6+, so 6 electrons are needed on the left):

Cr_2O_7^{2-} (aq) + 14 H^+ (aq) + 6e^-\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)

Similarly, tin(II) cation becomes tin(IV) cation:

Sn^{2+} (aq)\rightarrow Sn^{4+} (aq) + 2e^-

Now that we have the two half-equations, multiply the second one by 3, so that it also has 6 electrons that will be cancelled out upon addition of the two half-equations:

Cr_2O_7^{2-} (aq) + 14 H^+ (aq) + 6e^-\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l)

3 Sn^{2+} (aq)\rightarrow 3 Sn^{4+} (aq) + 6e^-

Add them together:

Cr_2O_7^{2-} (aq) + 14 H^+ (aq) + 3 Sn^{2+} (aq)\rightarrow 2 Cr^{3+} (aq) + 7 H_2O (l) + 3 Sn^{4+} (aq)

Adding the ions spectators:

K_2Cr_2O_7 (aq) + 14 HCl (aq) + 3 SnCl_2 (aq)\rightarrow 2 CrCl_3 (aq) + 7 H_2O (l) + 3 SnCl_4 (aq) + 2 KCl (aq)

7 0
3 years ago
Which of the following is a function of the geosphere
rewona [7]

The geosphere is where the earths crust, mantle, etc take place. Geosphere is where all the rocks take place in the earth.

Please mark as brainliest!

4 0
3 years ago
Show a correct numerical setup for calculating the
valkas [14]

0.25 moles of CO2 is present in 11 grams of CO2.

Explanation:

A mole represents the number of chemical entities in an element or molecule.

Number of moles of an element or molecule is determined by the formula:

The Number of moles (n) = weight of the atom given  ÷ atomic or molecular weight of the one mole of the element or molecule.

Themolar mass of one mole of carbon dioxide is:

12+ ( 16×2)

= 44 gram/mole

The given weight is 44 grams of carbon dioxide.

Putting the values in the equation,

n= 11 gms÷44 gms/ mole

n   = 0.25 mole

7 0
3 years ago
The fastest train in the world can travel 1,500 kilometers in 3 hours. What is its speed?
yanalaym [24]
500
hope this helps!
4 0
2 years ago
A 12 gram piece of metal is heated to 300 °C from 100 °C with 1120 Joules of energy. What is the specific heat of the metal?
Sergeeva-Olga [200]

Answer:

The specific heat for the metal is 0.466 J/g°C.

Explanation:

Given,

Q = 1120 Joules

mass = 12 grams

T₁ = 100°C

T₂ = 300°C

The specific heat for the metal can be calculated by using the formula

Q = (mass) (ΔT) (Cp)

ΔT = T₂ - T₁ = 300°C  - 100°C   = 200°C

Substituting values,

1120 = (12)(200)(Cp)

Cp = 0.466 J/g°C.

Therefore, specific heat of the metal is 0.466 J/g°C.

7 0
3 years ago
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