The frog's launch speed and the time spends in the air are 22.5m/s and 2.73s respectively.
To find the answer, we need to know about the time of flight and range of projectile motion.
<h3>What's the expression of range of a projectile motion?</h3>
- Range = U²× sin(2θ)/g
- U= initial velocity, θ= angle of projectile and g= acceleration due to gravity
- U=√{Range×g/sin(2θ)}
- Here, range= 2.20m, = 36.5°
- U= √{2.20×9.8/sin(73)}
U= √{2.20×9.8/sin(73)} = 22.5m/s
<h3>What's the expression of time of flight in projectile motion?</h3>
- Time of flight= (2×U×sinθ)/g
- So, T= (2×22.5×sin36.5°)/9.8
= 2.73 s
Thus, we can conclude that the frog's launch speed and the time spends in the air are 22.5m/s and 2.73s respectively.
Learn more about the range and time period of projectile motion here:
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Answer:

Explanation:
We know that speed is given by dividing distance by time or multiplying length and frequency. The speed of the father will be given by Lf where L is the length of the father’s leg ad f is the frequency.
We know that frequency of simple pendulum follows that 
Now, the speed of the father will be
while for the child the speed will be 
The ratio of the father’s speed to the child’s speed will be

As the metal expands as does the road bed so neither really effevts those foing over the bridge. as it is hot the metal will expand and so will most tarmac on roads.
Answer:Greenhouse effect
Explanation:
Short wavelength radiation from the sun passes through a planet's atmosphere but some of the outgoing long-wavelength energy is absorbed and radiated again this process is known as Green house effect which increases the temperature of earth and as a result causes more to be trapped inside earth atmosphere.
If the wavelength of a sound wave increases and the frequency of the sound wave does not change, the speed of the wave will increase.
Ans: D
Explanation
The sound wave speed is given by E=fλ, where f indicates its frequency and λ indicates its wavelength.
From the equation, it is evident that the sound speed is proportional to both frequency and wavelength.
Here, as wavelength increases, wave speed increases provided there is no change in frequency.