Pls fast as you can it is a test pls pls

Which of the following statements is true regarding the constructive interference diagram shown below? Select all that apply.

yulyashka [42]

Answer:

I believe its B and C

Explanation:

<u><em>If I'm wrong please tell me so I can correct my answer.</em></u>

6 0

2 years ago

Read 2 more answers

What's the formula to find out power

Julli [10]

In general,

   Power = (energy moved) / (time to move the energy) .

If it's mechanical power, then

   Power = (work done) / (time to do the work) .

If it's electrical power, then it can be any one of these:

   Power = (volts) x (amperes)

   Power = (volts)² / (resistance, ohms)

   Power = (amperes)² x (resistance, ohms) .

Whatever kind of energy you're dealing with, power always
turns out to be

(amount of energy produced, used, or moved)
divided by
(time taken to produce, use, or move the energy) .

3 0

3 years ago

F each fission reaction in a nuclear reactor emits three neutrons, how many neutrons are produced from three fission reactions?

IrinaK [193]

The Three fission reactions will produce nine neutrons

<h3>Meaning of Fission</h3>

Fission can be defined as a nuclear process that involves the breaking of a whole nuclear matter into smaller bits.

In a fission reaction, the matter is broken down into simpler bits.

In conclusion, The Three fission reactions will produce nine neutrons

Learn more about fission:brainly.com/question/3992688

#SPj1

8 0

2 years ago

Is noise energy a kind of energy or not

Volgvan

Yes. sound waves are produced by energy.

4 0

3 years ago

A space station has a large ring-like component that rotates to simulategravity for the crew. This ring has a massM= 2.1×105kg a

ivann1987 [24]

Answer:

Each thruster has to applied a force of 294.5N in tangential direction

Explanation:

Mass of the ring ,M =2.1×105kg

Mass of the ship ,m = 3.5×104kg

Radius of the ring R = 86.0 m

distance of ship from center of the ring, r =31.0 m

Let force applied by each thruster be F

Time taken to reach gravity ,t = 3hrs = 3600× 3 =10800sec

The movement of ring make the object kept at the edge feel a force of centrifuge in outward direction.

Centrifugal force = weight of the object on earth

Assume the ring is moving with angular speed ω

Centripetalforce of the object kept at ring

m₁R ω²=m₁g (m₁=mas of object)

⇒Rω² = g

⇒ω = √g/R

The ring start from 0 angular speed with constant angular acceleration

Let the constant angular acceleration be ∝

∝ = ω / t

(ω = √g/R)

∝ = $\frac{1}{t } \sqrt{\frac{g}{R} } }$

Consider Torque on the ring and ship system

T = FR + FR = 2FR

Moment of inertia of ring ship system

I = I(ring)+I(ship)+I(ship)

= MR² + mr² + mr² = MR² + 2mr²

angular acceleration of the ring ship system

∝ = $\frac{2FR}{MR^2 + 2mr^2}$

Now we have ,

∝ = $\frac{1}{t} \sqrt{\frac{g}{R} }$ , ∝ = $\frac{2FR}{MR^2+2mr^2}$

equating both values

We have,

$F = \frac{MR^2+2mr^2}{2Rt} \sqrt{\frac{g}{R} }$

where,

m = 2.1 × 10⁵kg, R = 86m, m = 3.5 × 10₄kg,

r = 31m, g = 9.8m/s² , t = 10800sec

$F = \frac{(2.1 \times 10^5 \times86^2)+(2\times3.5v10^4\times31^2) }{2\times86\times10800} \times\sqrt{\frac{9.8}{86} } \\\\F = 294.47N\\\approx294.5N$

Each thruster has to applied a force of 294.5N in tangential direction

3 0

3 years ago