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drek231 [11]
2 years ago
9

What is the distance fallen for a freely falling object 1 s after being dropped from a rest position? What is the distance for a

4-s drop?
Physics
1 answer:
kondor19780726 [428]2 years ago
5 0
<h2>Distance traveled in 1 second after drop is 4.9 m</h2><h2>Distance traveled in 4 seconds after drop is 78.4 m</h2>

Explanation:

We have s = ut + 0.5at²

For a free falling object initial velocity u = 0 m/s and acceleration due to gravity, g = 9.8 m/s²

Substituting

                 s = 0 x t + 0.5 x 9.8 x t²

                 s = 4.9t²

We need to find distance traveled in 1 s and 4 s

Distance traveled in 1 second

                   s = 4.9 x 1² = 4.9 m

Distance traveled in 4 seconds

                   s = 4.9 x 4² = 78.4 m

Distance traveled in 1 second after drop = 4.9 m

Distance traveled in 4 seconds after drop = 78.4 m

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Explanation:

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A small metal ball is suspended from the ceiling by a thread of negligible mass. The ball is then set in motion in a horizontal
Gemiola [76]

Answer:

Time taken, T=2\pi \sqrt{\dfrac{l\ cos\theta}{g}}

Explanation:

It is given that, a small metal ball is suspended from the ceiling by a thread of negligible mass. The ball is then set in motion in a horizontal circle so that the thread’s trajectory describes a cone as shown in attached figure.

From the figure,

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Let t is the time taken for the ball to rotate once around the axis. It is given by :

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Put the value of T from equation (2) to the above expression:

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Hence, this is the required solution.

4 0
3 years ago
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