All categories

3 years ago

a solid with a low melting point is most likely what? A.ionic B. covalent C. metallic or D. None of the above.

1 answer:

3 0

The correct answer of the given question above would be option D. None of the above. When a solid has a low melting point, it is most likely a simple molecular substance. When it is ionic, covalent or metallic, it is already considered as a solid with a high melting point.

You might be interested in

8.310x10^2 – 7.210x10^1 [?]x10^[?]

alisha [4.7K]

Answer:

$7.589\times 10^{2}$

Explanation:

The expression can be solved mathematically as follows:

1) $8.310\times 10^{2}-7.210\times 10^{1}$ Given

2) $8.310\times 10^{1+1} - 7.210\times 10^{1}$ Definition of sum

3) $(8.310\times 10^{1})\times 10^{1}-7.210\times 10^{1}$ $a^{m+n} = a^{m}\cdot a^{n}$ /Associative property

4) $(8.310\times 10^{1}-7.210)\times 10^{1}$ Distributive property

5) $(83.100-7.210)\times 10^{1}$ Multiplication

6) $75.89\times 10^{1}$ Subtraction.

7) $(7.589\times 10^{1})\times 10^{1}$ Multiplication/Associative property

8) $7.589\times (10^{1}\times 10^{1})$ Associative property

9) $7.589\times 10^{2}$ $a^{m+n} = a^{m}\cdot a^{n}$ /Result

7 0

2 years ago

Octane has a density of 0.703 g/ml. Calculate the mass of CO2(g) produced by burning one

STatiana [176]

The mass of CO₂ gas produced during the combustion of one gallon of octane is 8.21 kg.

The given parameters:

Density of the octane, ρ = 0.703 g/ml
Volume of octane, v = 3.79 liters

The mass of the octane burnt is calculated as follows;

$m = \rho V\\\\m = 0.703 \ \frac{g}{ml} \times 3.79 \ L \ \frac{1000 \ ml}{L} \\\\m = 2,664.37 \ g$

The combustion reaction of octane is given as;

$2C_8H_{18} + \ 25O_2 \ --> \ 16CO_2 \ + \ 18H_2O$

From the reaction above:

228.46 g of octane -------------------> 704 g of CO₂ gas

2,664.37 of octane --------------------> ? of CO₂ gas

$= \frac{2,664.37 \times 704}{228.46} \\\\= 8,210.3 \ g\\\\= 8.21 \ kg$

Thus, the mass of CO₂ gas produced during the combustion of one gallon of octane is 8.21 kg.

Learn more about combustion of organic compounds here: brainly.com/question/13272422

8 0

2 years ago

How much of a 50g sample of 85Kr will remain after 2 half-lives?

Rashid [163]

Answer:

i need help with my work

Explanation:

8 0

3 years ago

What would be the bond order for He 2 2- molecule

LuckyWell [14K]

Answer:

In He2 molecule,

Atomic orbitals available for making Molecular Orbitals are 1s from each Helium. And total number of electrons available are 4.

Molecular Orbitals thus formed are:€1s2€*1s2

It means 2 electrons are in bonding molecular orbitals and 2 are in antibonding molecular orbitals .

Bond Order =Electrons in bonding molecular orbitals - electrons in antibonding molecular orbitals /2

Bond Order =Nb-Na/2

Bond Order =2-2/2=0

Since the bond order is zero so that He2 molecule does not exist.

Explanation:

8 0

3 years ago

Look at the periodic table. Find the element carbon. What is its symbol?

Sliva [168]

A. ca is the answer because its short for carbon

6 0

3 years ago

Read 2 more answers