Glacial erosion is the process by which a glacial flows over the land, picking up rocks.
Hello Olivia!!!
<span>Q.) Describe at least two geological events that can occur at a divergent boundary.
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A.)Most active divergent plate boundaries occur between oceanic plates and exist as mid-oceanic ridges. Divergent boundaries also form volcanic islands which occur when the plates move apart to produce gaps which molten lava rises to fill.
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Answer:
The mass of water = 219.1 grams
Explanation:
Step 1: Data given
Mass of aluminium = 32.5 grams
specific heat capacity aluminium = 0.921 J/g°C
Temperature = 82.4 °C
Temperature of water = 22.3 °C
The final temperature = 24.2 °C
Step 2: Calculate the mass of water
Heat lost = heat gained
Qlost = -Qgained
Qaluminium = -Qwater
Q = m*c*ΔT
m(aluminium)*c(aluminium)*ΔT(aluminium) = -m(water)*c(water)*ΔT(water)
⇒with m(aluminium) = the mass of aluminium = 32.5 grams
⇒with c(aluminium) = the specific heat of aluminium = 0.921 J/g°C
⇒with ΔT(aluminium) = the change of temperature of aluminium = 24.2 °C - 82.4 °C = -58.2 °C
⇒with m(water) = the mass of water = TO BE DETERMINED
⇒with c(water) = 4.184 J/g°C
⇒with ΔT(water) = the change of temperature of water = 24.2 °C - 22.3 °C = 1.9 °C
32.5 * 0.921 * -58.2 = -m * 4.184 * 1.9
-1742.1 = -7.95m
m = 219.1 grams
The mass of water = 219.1 grams
Thermoplastic and thermosetting
thermoplastic:- they are easily molded and extruded into films, fibres and packaging.For eg. PVC
thermosetting:-they are hard and durable and can be used for aircraft parts,tires and auto parts .For eg. phenolic resins.
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Answer:
The answer to your question is 6.54 g of H₂O
Explanation:
Data
mass of water = ?
mass of carbon dioxide = 16 g
Balanced chemical reaction
H₂CO₃ ⇒ H₂O + CO₂
Process
1.- Calculate the molar mass of the products
H₂O = (1 x 2) + (1 x 16) = 2 + 16 = 18 g
CO₂ = (1 x 12) + (16 x 2) = 12 + 32 = 44 g
2.- Use proportions and cross multiplication to solve this problem.
18 g of H₂O -------------------- 44 g of CO₂
x -------------------- 16 g of CO₂
x = (16 x 18) / 44
x = 288/44
x = 6.54 g of H₂O