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morpeh [17]
3 years ago
7

How are parallel circuits used in homes?

Physics
1 answer:
zhannawk [14.2K]3 years ago
5 0
Every single thing in your home that's plugged into a wall outlet or works with a switch on the wall . . . every lamp, ceiling light, room fan, computer, microwave, stove, hair dryer, coffee pot, toaster, slow cooker, TV, home entertainment system, printer, wifi router, cordless phone, phone charger, and clock radio ...  they're ALL in parallel.

<u>And</u> chances are that everything in your house is also in parallel with everything in the houses of a few of your neighbors on each side of you.

THAT's how parallel circuits are used in residential areas.
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A student pushes a box with a total mass of 50 kg. What is the net force on the box if it accelerates 1.5 m/s
Harrizon [31]
We now that follow newton rules f=ma so net force equal to mass*acceleration=>f=50*1.5=75 N
3 0
3 years ago
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A spherical Christmas tree ornament is 8.00 cm in diameter. What is the magnification of an object placed 12.0 cm away from the
LiRa [457]

The magnification of the ornament is 0.25

To calculate the magnification of the ornament, first, we need to find the image distance.

Formula:

  • 1/f = u⁻¹+v⁻¹.................... Equation 1

Where:

  • f = Focal length of the ornament
  • u = image distance
  • v = object distance.

make u the subject of the equation

  • u = fv/(f+v)................ Equation 2

From the question,

Given:

  • f = 8/2 = 4 cm
  • v = 12 cm

Substitute these values into equation 2

  • u = (12×4)/(12+4)
  • u = 48/16
  • u = 3 cm.

Finally, to get the magnification of the ornament, we use the formula below.

  • M = u/v.................. Equation 3

Where

  • M = magnification of the ornament.

Substitute these values above into equation 3

  • M = 3/12
  • M = 0.25.

Hence, The magnification of the ornament is 0.25

8 0
3 years ago
Gold-leaf electroscope uses
Kruka [31]
-identifies an electric charge 
-it can identify its polarity (positive or negative) if you compare it to a charge that you already know
-can identify the magnitude of a charge (how big of a charge it is)
7 0
4 years ago
12000 inches to yards
Nutka1998 [239]

ANSWER

\begin{equation*} 333.33\text{ yds} \end{equation*}

EXPLANATION

We want to convert 12000 inches to yards.

To do this, divide the value in inches by 36:

\begin{gathered} 1\text{ in }=\frac{1}{36}\text{ yd} \\  \\ 12000\text{ in }=\frac{12000}{36}\text{ yds }=333.33\text{ yds} \end{gathered}

That is the answer.

4 0
1 year ago
190 kg of water is to be raised by a water pump to a height of 25 meters from the bottom of a well in 60 seconds. What should be
ladessa [460]

Answer:

776.6 w

1.04 hp

Explanation:

given:

Mass, m = 190kg

height change, h = 25m

time elapsed, t = 60 s

acceleration due to gravity, g = 9.81 m/s²

Potential energy required raising 190 kg of water to a height of 25m

= mgh

= 190 x 9.81 x 25

= 46,597.5 J

Power required in 60 s

= Energy required ÷ time elapsed

= 46,597.5 ÷ 60

= 776.6 Watts  (Use conversion 1 W = 0.00134102 hp)

= 776.6 w x 0.00134102 hp/w

= 1.04 hp

6 0
3 years ago
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