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2 years ago

13

A leaky faucet drips 40 times in 30.0 s. what is the frequency of the dripping?

1 answer:

Dmitrij [34]2 years ago

6 0

The answer is 40/30 which is 1.3 Hz.

Hope this helps. :)

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A lone neutron spontaneously decays into a proton plus an _______

frosja888 [35]

Answer:

A lone neutron spontaneously decays into a proton plus an electron.

Explanation:

In an atom, nuclei contain protons and neutrons, which are the fundamental particles of an atom. Neutrons are stable and uncharged particles inside a nucleus.

For 15 times during its lifetime, a free neutron decays and breaks down into more smaller particles.This breakdown causes problems in nuclear reactors, as they start decaying and emit radiations of different wavelengths.

A neutron undergoes the decaying process to produce an electron, a proton, and energy.

The reaction of neutron decay:

n0 → p+ + e− + νe

5 0

3 years ago

The location of the strongest magnetic force is the

Elenna [48]

Answer:

The north pole has the strongest magnetic force

6 0

2 years ago

An electron is released from rest at a distance of 0.470 m from a large insulating sheet of charge that has uniform surface char

ArbitrLikvidat [17]

Answer:

Part a)

$W = 1.58 \times 10^{-20} J$

Part b)

$v = 1.86 \times 10^5 m/s$

Explanation:

Part a)

Electric field due to large sheet is given as

$E = \frac{\sigma}{2\epsilon_0}$

$\sigma = 4.00 \times 10^{-12} C/m^2$

now the electric field is given as

$E = \frac{4.00 \times 10^{-12}}{2(8.85 \times 10^{-12})}$

$E = 0.225 N/C$

Now acceleration of an electron due to this electric field is given as

$a = \frac{eE}{m}$

$a = \frac{(1.6 \times 10^{-19})(0.225)}{9.1 \times 10^{-31}}$

$a = 3.97 \times 10^{10}$

Now work done on the electron due to this electric field

$W = F.d$

$d = 0.470 - 0.03$

$d = 0.44 m$

So work done is given as

$W = (ma)(0.44)$

$W = (9.11 \times 10^{-31})(3.97 \times 10^{10})(0.44)$

$W = 1.58 \times 10^{-20} J$

Part b)

Now we know that work done by all forces = change in kinetic energy of the electron

so we will have

$W = \frac{1}{2}mv^2 - 0$

$1.58 \times 10^{-20} = \frac{1}{2}(9.1\times 10^{-31})v^2$

$v = 1.86 \times 10^5 m/s$

7 0

3 years ago

What kind of engine do most cars use today

Nadusha1986 [10]

Answer:

4 stroke 4 cylinder Natural Aspirated Gasoline engine

Explanation:

im not 100% sure

4 0

2 years ago

Read 2 more answers

A sound wave can be considered as a displacement wave or a pressure wave? What phase difference exists between the displacement

netineya [11]

Where the displacement is a maximum the pressure is a minimum.
Where the displacement is zero, the pressure is a maximum.

3 0

3 years ago