Answer:
(2A)/h -a =b
Step-by-step explanation:
A= [h(a+b)]/2 I rewrote the formula, because h and a+b are in the numerator.
2A=h(a+b) Multiply both sides of equation by 2
(2A)/h= a+b Divide both side by h
(2A)/h -a= b Subtract a from both sides
The answer is A
You can solve this by equation the two equations, by substitution method or elimination. Let's choose the substitution since Equation 2 has already X isolated
-take the X in equation 2 and substitute in the first equation
So, You should have 5 (5-3/2 y) -4y =7
Get y ( I'll assume you know how to simplify and find y by yourself )
y=36/23
-Now take y and substitute it in the first equation or the second equation (it doesn't really matter)
Substituting y in Equation 2:
x=5- 3/2 (36/23)
=> x= 61/23
So answer is A where (x,y) is (61/23, 36/23)
Answer:
1.12 × 10^-3
Step-by-step explanation:
The computation of the width of the photograph is as follows:
As we know that
Area of the rectangle = length × width
33 ÷ 20 square inches = 1475 inches × width
So, the width is
= Length ÷ area
= 1475 inches ÷ (33 ÷ 20 square inches)
= 1.12 × 10^-3
Answer:
6. xint=-7
yint=-3
7. xint=-7
yint=-5
Step-by-step explanation:
