1) |x| is the absolute value function. Its vertex is at (0,0).
2) |x-1| has the same graph as does y = |x|, except that the vertex is shifted 1 unit to the left.
3) -3|x-1| has the same graph as the previous result, except that we must reflect the previous graph in the x-axis.
4) Replace the solid lines you used in this graph with dashed ones.
5) Shade the area beneath y = -3|x-1|
In summary:
the desired graph is the shaded area below the inverted v-shaped graph of
y = -3|x-1|. Its vertex is at (-1,0).
Answer:
looks like a line kinda
Step-by-step explanation:
What you want to do is take one of the 2 equations and isolate one variable. you will then use the value that you find for the variable and plug it back into the other equation. here is how:
This would be easiest to do with the second equation in the set since the x is not being multiplied by anything. So lets isolate the x in the second equation.
add 0.9y to both sides and you get:
x=4.5+0.9y
we now know what x is equal to in terms of y. so lets replace the x in the first equation with the new value. You get:
1.5(4.5+0.9y)-1.9y=-29
Now just solve for y:
6.75+1.35y-1.9y=-29
1.35y-1.9y=-35.75
-0.55y=-35.75
y=65
so now you know that y=65 so plug 65 in as y in the second equation to find x
x-0.9*65=4.5
Now simply solve for x
x-(-58.5)=4.5
x+58.5=4.5
x=-54
Hope this helped! :)
Yes, this can happen if the rectangles are the same dimensions, BUT NO if the dimensions are different.
Answer:
answer is 111
Step-by-step explanation:
