Each of the Isotopic mass * its Abundance Sum together divide by 100.
(179.946706*0.12 + 181.948206*26.5 + 182.9502245*14.3 + 183.9509326*30.64 + 185.954362*28.43 ) / 100
You get 183.84 (5s.f. ) or (183.8417786)
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Answer:
Option B. 176g/mol
Explanation:
We'll begin by writing the chemical formula for hexasodium difluoride. This is given below:
Hexasodium means 6 sodium atom
Difluoride means 2 fluorine atom.
Therefore, the formula for hexasodium difluoride is Na6F2.
The relative formula mass of a compound is obtained by simply adding the atomic masses of the elements present in the compound.
Thus, the relative formula mass of hexasodium difluoride, Na6F2 can be obtained as follow:
Molar mass of Na = 23g/mol
Molar mass of F = 19g/mol
Relative formula mass Na6F2 = (23x6) + (19x2)
= 138 + 38
= 176g/mol
Therefore, the relative formula mass of hexasodium difluoride, Na6F2 is 176g/mol
Octane has stronger London dispersion forces than ethane
Answer:
A is the answer
Explanation:
See, let me explain it first of all.
Because, We all know every drop of water is being evaporated from the seas, streams, oceans,etc. So, the statement is wrong about it. It is wrong. How can't water get evaporated from the seas and the streams,etc.
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Answer:
1.) ⁴₂He
2.) ⁶₂He
3.) ²⁴²₉₄Pu
4.) ¹₀n
Explanation:
The superscript represents the mass number, which is the total amount of protons and neutrons in an element.
The subscript represents the atomic number, which is the total amount of protons in an element.
You can identify the element based on the atomic number. For instance, all atoms with a subscript/atomic number of 2 must always be helium (He). An element with an atomic number of 0 is represented by the symbol "n". The mass number and atomic numbers must be equal on both sides of the reaction.
1.) ¹₁H + ³₁H → ⁴₂He
-----> Mass Number: 1 + 3 = 4
-----> Atomic Number: 1 + 1 = 2
2.) ⁹₄Be + ¹₁H → He + ⁶₂He
-----> Standard helium (He) has a mass number of 4 and an atomic number of 2
-----> Mass Number: 9 + 1 - 4 = 6
-----> Atomic Number: 4 + 1 - 2 = 2
3.) ²³⁹₉₂U + ⁴₂He → ²⁴²₉₄Pu + ¹₀n
-----> Mass Number: 239 + 4 - 1 = 242
-----> Atomic Number: 92 + 2 - 0 = 94
4.) ²⁷₁₃Al + ¹₀n → ²⁴₁₁Na + ⁴₂He
-----> Mass Number: 24 + 4 - 27 = 1
-----> Atomic Number: 11 + 2 - 13 = 0