Ask question

Ask question

All categories

3 years ago

15

why is it essential to know the water temperature in this experiment- to find the vapor pressure of the water

1 answer:

Oksi-84 [34.3K]3 years ago

5 0

Answer:

Vapour pressure of a liquid varies with temperature

Explanation:

The vapour pressure of any liquid is directly proportional to the temperature of the liquid. This implies that, as the temperature of the liquid increases, the vapour pressure increases likewise and vice versa.

Since the vapour pressure of liquid varies with the temperature of the liquid, it is essential to know the water temperature in the experiment to determine the vapour pressure of water.

You might be interested in

When hydrogen chloride (HCI) reacts with ammonia (NH3), ammonium chloride (NH4CI) is

givi [52]

Answer:

AMEN NNNNNNNNNNNNNNNNNNNNNNNN

6 0

3 years ago

How many moles are contained in a 4.67-l sample of gas at 30°c and 199 kpa?

ohaa [14]

Pv=nRT
where,p=199, R(constant)=8.314, V=4.67 T=30C=293K
n=pv/RT=0.38 moles

4 0

3 years ago

Read 2 more answers

The density of potassium, which has the BCC structure, is 0.855 g/cm3. The atomic weight of potassium is 39.09 g/mol. Calculate

Nimfa-mama [501]

Answer:

lattice parameter = 5.3355x10^-8 cm

atomic radius = 2.3103x10^-8 cm

Explanation:

known data:

p=0.855 g/cm^3

atomic mass = 39.09 g/mol

atoms/cell = 2 atoms

Avogadro number = 6.02x10^23 atom/mol

a) the lattice parameter:

Since potassium has a cubic structure, its volume is equal to:

v = [(atoms/cell)x(atomic mass)/(p)x(Avogadro number)]

substituting values:

v =[(2)x(39.09)/(0.855x6.02x10^23)]=1.5189x10^-22 cm^3

but as the cell volume is

a^3 =v

$a=\sqrt[3]{v}=\sqrt[3]{1.5189x10^{-22} } = 5.3355x10^-8$ cm

for a BCC structure, the atomic radius is equal to

$r=\frac{ax\sqrt{3} }{4}=\frac{5.3355x10^{-8}x\sqrt{3} }{4}=2.3103x10^{-8}cm$

7 0

3 years ago

Who made the periodic table?

swat32

Nobody specifically made the periodic table but it was first thought of by Dmitri Mendeleev in 1869.

7 0

3 years ago

Read 2 more answers

4. If 0.130 g of p-aminophenol is allowed to react with excess acetic anhydride, what is the theoretical yield of acetaminophen

Dominik [7]

Hey There!

p-aminophenol (109.13 g/mol) + Ac2O (102.09 g/mol) ---> acetominophen (151.16 g/mol)

next, since you already know your limiting reactant (p-aminophenol), convert it to mols :

0.130 g / (109.13 g/mol) = 0.00119 moles

now that's your theoretical max, since its a 1:1 mol ratio, so multiply by the new molecular weight. :

0.00119 * 151.16 = 0.180 g

Hope that helps!

8 0

2 years ago