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Vera_Pavlovna [14]
3 years ago
5

can someone please help me with these questions? predicting products and balancing the equations of single replacement​

Chemistry
1 answer:
FinnZ [79.3K]3 years ago
4 0
Put the metal with the non-metal and use the charges to figure it out
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Given what we know, we can confirm that hair gel is considered a noncrystalline solid due to Atoms in the hair gel having no particular order or pattern.

<h3>What is a noncrystalline solid?</h3>
  • This is a solid whose atoms are amorphous.
  • What this means is that the atoms lack a specific order like most solids.
  • The most common example of this is glass.

Therefore, given the definition of a noncrystalline solid as a solid whose atoms lack a specified order, we can confirm that the second option which states that "Atoms in the hair gel having no particular order or pattern" is correct.

To learn more about Atoms visit:

brainly.com/question/13981855?referrer=searchResults

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Arenediazoniums can undergo electrophilic aromatic substitutions with a wide variety of activated aromatic compounds to yield ne
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Why is it called endogenous process
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The Earth is shaped by many geological processes. ... Processes caused by forces from within the Earth are endogenous processes. Exo is a prefix meaning "out", and endo is a prefix meaning "in". Many exogenous (extraterrestrial) forces are caused by other bodies in the Solar System.

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3 years ago
Consider the nuclear equation below. 239/94 Pu—-&gt; X+ 4/2 He. What is X?
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4 0
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Using any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 30.0 °C for the following reacti
gayaneshka [121]

Answer : The value of K for this reaction is, 2.6\times 10^{15}

Explanation :

The given chemical reaction is:

CH_3OH(g)+CO(g)\rightarrow HCH_3CO_2(g)

Now we have to calculate value of (\Delta G^o).

\Delta G^o=G_f_{product}-G_f_{reactant}

\Delta G^o=[n_{HCH_3CO_2(g)}\times \Delta G^0_{(HCH_3CO_2(g))}]-[n_{CH_3OH(g)}\times \Delta G^0_{(CH_3OH(g))}+n_{CO(g)}\times \Delta G^0_{(CO(g))}]

where,

\Delta G^o = Gibbs free energy of reaction = ?

n = number of moles

\Delta G^0_{(HCH_3CO_2(g))} = -389.8 kJ/mol

\Delta G^0_{(CH_3OH(g))} = -161.96 kJ/mol

\Delta G^0_{(CO(g))} = -137.2 kJ/mol

Now put all the given values in this expression, we get:

\Delta G^o=[1mole\times (-389.8kJ/mol)]-[1mole\times (-163.2kJ/mol)+1mole\times (-137.2kJ/mol)]

\Delta G^o=-89.4kJ/mol

The relation between the equilibrium constant and standard Gibbs, free energy is:

\Delta G^o=-RT\times \ln K

where,

\Delta G^o = standard Gibbs, free energy  = -89.4 kJ/mol = -89400 J/mol

R = gas constant  = 8.314 J/L.atm

T = temperature  = 30.0^oC=273+30.0=303K

K = equilibrium constant = ?

Now put all the given values in this expression, we get:

-89400J/mol=-(8.314J/L.atm)\times (303K)\times \ln K

K=2.6\times 10^{15}

Thus, the value of K for this reaction is, 2.6\times 10^{15}

4 0
3 years ago
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