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3 years ago

How many non bonded electron pairs are in the tetracyanoethylene molecule?

Chemistry

2 answers:

algol [13]3 years ago

8 0

Each of the Nitrogen atoms has 2 non bonded valence electrons, meaning that there are 4 pairs total.

Ganezh [65]3 years ago

3 0

Answer:

There are 4 non bonded electron pair in tetracyanoethylene

Explanation:

In tetracyanoethylene, four cyano groups are attached with an ethylene moiety.
Non bonded electron pairs in tetracyanoethylene molecule are present on N atoms in cyano groups.
Each N atom in a cyano group contains one non bonded electron pair.
There are 4 cyano groups in tetracyanoethylene.
Hence there are 4 non bonded electron pair in tetracyanoethylene.
Lewis structure of tetracyanoethylene has been given below.

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What is the element for Trifluoroborane

Harlamova29_29 [7]

<span>Ethoxyethane; trifluoroborane; BF3.Et2O; Boron trifluoride ethyl ether; Boron trifluoride diethyl ether; Boron trifluoride-diethyl ether; Boron

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7 0

3 years ago

What is the hydronium ion concentration of a 0.100 M acetic acid solution with Ka = 1.8 × 10-5? The equation for the dissociatio

evablogger [386]

Answer:

1.3×10⁻³ M

Explanation:

Hello,

In this case, given the dissociation reaction of acetic acid:

$CH_3CO_2H(aq) + H_2O(l) \rightleftharpoons H_3O^+(aq) + CH_3CO_2^-(aq)$

We can write the law of mass action for it:

$Ka=\frac{[H_3O^+][CH_3CO_2^-]}{[CH_3CO_2H]}$

Of course, excluding the water as heterogeneous substances are not included. Then, in terms of the change $x$ due to the dissociation extent, we are able to rewrite it as shown below:

$1.8x10^{-5}=\frac{x*x}{0.100-x}$

Thus, via the quadratic equation or solve, we obtain the following solutions:

$x_1=-0.00135M\\x_2=0.00133M$

Obviously, the solution is 0.00133M which match with the hydronium concentration, thus, answer is: 1.3×10⁻³ M in scientific notation.

Regards.

8 0

4 years ago

Read 2 more answers

A relationship between two organisms that benefits both organisms is called

Alex777 [14]

Answer:

Mutualism

Explanation:

A relationship in which both benefit

3 0

3 years ago

When temperatures are below freezing, the temperature at which air becomes saturated leading to the formation of frost is the

12345 [234]

Answer:

The answer is Frost Point.

Explanation:

The temperature to which the air must be cooled, with constant pressure, to reach saturation (in relation to liquid water), is called the dew point. The dew point gives a measure of the water vapor content in the air. The higher, the greater the concentration of water vapor in the air. However, when cooling produces saturation at a temperature of 0 ° C or less, the temperature is called a frost point. The water vapor is deposited as frost on a surface whose temperature is below the dew point.

4 0

3 years ago

1-propanol (P1° = 20.9 Torr at 25 °C) and 2-propanol (P2° = 45.2 Torr at 25 °C) form ideal solutions in all proportions. Let x1

jekas [21]

Answer:

y1 = 0.3162

y2 = 0.6838

Explanation:

ok let us begin,

first we would be defining the parameters;

at 25°C;

1-propanol P1° = 20.90 Torr

2-propanol P2° = 45.2 Torr

From Raoults law:

P(1-propanol) = P⁰ × X(1-propanol)

P(1-propanol) = 20.9 torr × 0.45 = 9.405

P(1-propanol) = 9.405 torr

Also P(2-propanol) = P⁰ × X(2-propanol)

P(2-propanol) = 45.2 torr × 0.45

P(2-propanol) = 20.34 torr

but the total pressure = sum of individual pressures

total pressure = 9.405 + 20.34

total pressure = 29.745 torr

given that y1 and y2 represent the mole fraction of each in the vapor phase

y1 = P1 / total pressure

y1 = 9.405/29.745

y1 = 0.3162

Since y1 + y2 = 1

y2 = 1 - y1

∴ y2 = 1 - 0.3162

y2 = 0.6838

cheers, i hope this helps.

7 0

3 years ago