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3 years ago

How many non bonded electron pairs are in the tetracyanoethylene molecule?

Chemistry

2 answers:

algol [13]3 years ago

8 0

Each of the Nitrogen atoms has 2 non bonded valence electrons, meaning that there are 4 pairs total.

Ganezh [65]3 years ago

3 0

Answer:

There are 4 non bonded electron pair in tetracyanoethylene

Explanation:

In tetracyanoethylene, four cyano groups are attached with an ethylene moiety.
Non bonded electron pairs in tetracyanoethylene molecule are present on N atoms in cyano groups.
Each N atom in a cyano group contains one non bonded electron pair.
There are 4 cyano groups in tetracyanoethylene.
Hence there are 4 non bonded electron pair in tetracyanoethylene.
Lewis structure of tetracyanoethylene has been given below.

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sergey [27]

Answer:

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3 years ago

In order to synthesize proteins, carbohydrates, lipids, and nucleic acids, cells require _____.

jonny [76]

Answer:

Energy

Explanation:

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3 years ago

In which case would an electron experience the greatest effective nuclear charge? not all cases describe an atom in the ground s

lisabon 2012 [21]

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5 0

1 year ago

Suppose a student started with 142.0 mg of trans-cinnamic acid, 412 mg of pyridinium tribromide, and 2.30 mL of glacial acetic a

nirvana33 [79]

Answer: Theoretical Yield = 0.2952 g

Percentage Yield = 75.3%

Explanation:

Calculation of limiting reactant:

n-trans-cinnamic acid moles = (142mg/1000) / 148.16 = 9.584*10⁻⁴ mol

pyridium tribromide moles = (412mg/1000) / 319.82= 1.288*10⁻³ mol

n-trans-cinnamic acid is the limiting reactant

The molar ratio according to the equation mentioned is equals to 1:1

The brominated product moles is also = 9.584*10⁻⁴ mol

Theoretical yield = (9.584*10⁻⁴ mol) * (Mr of brominated product)

= (9.584*10⁻⁴ mol) * (307.97) = 0.2952 g

Percentage Yield is : Actual Yield / Theoretical Yield = 0.2223/0.2952

= 75.3%

4 0

3 years ago

The periodic table is based on an element's

Stels [109]

The answer will be B.

4 0

2 years ago

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