Significant figures means the number of important figures, 0 not included.
This means that the answer is 1094.00
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Answer:
See figure 1
Explanation:
In this question, we have to start with the <u>protonation of the double bond</u>. In carvone we have two double bonds, so, we have to decide first which one would be protonated.
The problem states that the <u>terminal alkene</u> is the one that would is protonated. Therefore, we have to do the <u>protonation</u> in the double bond at the bottom to produce the <u>carbocation number 1</u>. Then, a hydride shift takes place to produce the <u>carbocation number 2</u>. A continuation, an <u>elimination reaction</u> takes place to produce the <u>conjugated diene</u>. Then the diene is protonated at the <u>carbonyl group</u> and with an elimination reaction of an hydrogen in the <u>alpha carbon</u> we can obtain <u>carvacol. </u>
Answer:
The answer to your question is: 1538095.2 kg of NH3
Explanation:
MW HNO3 = 63 kg
MW NO2 = 46 kg
3 NO2(g) + H2O(l)--- 2 HNO3(aq) + NO(g)
3(46) kg-------------- 2(63) kg
x --------------- 7600000 kg
x = 7600000 x 138/126 = 8323809.5 kg og NO2
MW NO = 30
2 NO(g) + O2(g)---2 NO2(g)
2(30) ------------------2(46)
x ---------------- 8323809.5 kg
x = 8323809.5 x 60/92 = 5428571.4 kg of NO
MW NH3 = 17 kg
4 NH3(g) + 5 O2(g) 4 NO(g) + 6 H2O(g)
4(17) -------------------- 4(30)
x ----------------------- 5428571.4
x = 5428571.4 x 34 / 120
x = 1538095.2 kg of NH3