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Otrada [13]
3 years ago
7

Am I incorrect ? Or nah?

Chemistry
2 answers:
castortr0y [4]3 years ago
7 0

Answer:

yes

Explanation:

Mademuasel [1]3 years ago
4 0
I think so... I'm currently learning this too but you should be correct
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The actual number of pennies in a jar is 218. You miscounted and came up with 215 pennies. What is your percent error?
Katyanochek1 [597]

Answer:

3%

Explanation:

Substract the actual error from the final and multiply by 100

6 0
3 years ago
Which of these is an indication that a chemical reaction has occurred?
Kobotan [32]

<u><em>Answer:</em></u>

  • The correct option is C.
  • Formation of a precipitate

<u><em>Explanation:</em></u>

During a chemical reaction, new substances are formed known as a products, mostly reaction occur and their product is obtained as precipitates.

<u><em>Example</em></u>

Arylidene-2-thiobarbituric acid is obtained as precipitates when aldehyde and thiobarbituric acid react to each other.

melting of a substance

It is just indication of physical changes, like melting of ice, composition remained same as before.

boiling of a substance

It is just indication of physical changes, like boiling of water into vapors, composition remained same as before.

freezing of a substance

It is just indication of physical changes, like freezing of water into ice, composition remained same as before

7 0
3 years ago
Read 2 more answers
What is all three states of matter?
Karo-lina-s [1.5K]
Solid, Liquid, and Gas
7 0
3 years ago
Read 2 more answers
Titration of a 20.0-mL sample of acid rain required 1.7 mL of 0.0811 M NaOH to reach the end point. If we assume that the acidit
Rasek [7]

Answer:

Concentration of sulfuric acid in the acid rain sample is 0.0034467 mol/L.

Explanation:

Volume of NaOH = 1.7 ml = 0.0017 L

Molarity of NaOH = 0.0811 M

Moles of NaOH = n

0.0811 M=\frac{n}{0.0017 L}

n = 0.0001378 mol

H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O

According to reaction, 2 mol of NaOH neutralize 1 mol of sulfuric acid.

Then 0.0001378 mol of NaOH will neutralize:

\frac{1}{2}\times 0.0001378 mol=6.8935\times 10^{-5} mol of sulfuric acid.

Concentration of sulfuric acid in the acid rain sample: x

x=\frac{6.8935\times 10^{-5}}{0.02 L}=0.0034467 mol/L

Concentration of sulfuric acid in the acid rain sample is 0.0034467 mol/L.

7 0
3 years ago
Can you please help me?
lorasvet [3.4K]

Answer:

60 moles of NaF

Explanation:

The balanced equation for the reaction is given below:

Al(NO3)3 + 3NaF —> 3NaNO3 + AlF3

From the balanced equation above,

3 moles of NaF reacted to produce 1 mole of AlF3.

Therefore, Xmol of NaF will react to produce 20 moles of AlF3 i.e

Xmol of NaF = 3 x 20

Xmol of NaF = 60 moles

Therefore, 60 moles of NaF are required to produce 20 moles of AlF3.

4 0
3 years ago
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