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3 years ago

HELP NOW PLEASE! ARE YOU SMART ENOUGH TO ANSWER THIS?

1 answer:

5 0

Since there are 9 values, to find the Lower Quartile and Upper Quartile, you use the first 4 values and the last 4 values.

For Q1, you average the middle to values of your first 4 values since 4 is an even number. In this case (22+25)/2=23.5.
You do the same for Q3. (32+33)/2=32.5
For the interquartile range, you subtract Q1 from Q3. So, 32.5-23.5=9

Therefore, your lower quartile is 23.5, upper quartile is 32.5 and the interquartile range is 9.

You might be interested in

Will a 11.5-inch x 18-inch rectangular tray fit in the box shown? Explain.

pychu [463]

Answer:

Option D

Step-by-step explanation:

From the picture attached,

In the parallelogram ABCD,

Length of diagonals AC and BD are equal.

By the property,

"If the lengths of the diagonals of a parallelogram are equal, parallelogram will be a rectangle".

Therefore ABCD is a rectangle.

That means all interior angles of the given rectangle will be 90°.

Now we apply Pythagoras theorem in right triangle ΔABC,

AC² = AB² + BC²

(22)² = (12)² + (BC)²

484 - 144 = (BC)²

BC = √340

BC = 18.44 inches

Dimensions of the given box are 12 inches by 18.44 inches.

Dimensions of the rectangular tray is 11.5 inches by 18 inches.

Since, dimensions of the box are larger than the dimensions of the tray, tray can be adjusted in the box.

Therefore, Option D will be the answer.

3 0

3 years ago

3/5 of the students in a classroom are girls if there are 10 boys in the class how many total students are there

nata0808 [166]

16 students is the correct answer...
for every 5 boys there are 3 girls, so 20 boys 6 girls = the total of 16 students

8 0

3 years ago

Please help ( angles )

svlad2 [7]

Answer: 55%

Step-by-step explanation: 100%-45%=55%

7 0

3 years ago

Read 2 more answers

What is the cube root of -729a^9b^6? -9a^3b^2 -9a^2b^ -8a^3b^2 -8a^2b^3

timurjin [86]

Answer:

$= 9a^3b^2$

Step-by-step explanation:

$\sqrt[3]{-729a^9b^6} =$

$= ((-9)^3a^9b^6)^{\frac{1}{3}$

$= (-9)^{3 \times \frac{1}{3}} \times a^{9 \times \frac{1}{3}} \times b^{6 \times \frac{1}{3}}$

$= (-9)^{1} \times a^{3} \times b^{2}$

$= -9a^3b^2$

7 0

2 years ago

PLZ I WILL GIVE BRAILIEST TO THE FIRST ANSWER

natima [27]

Option B is the correct answer.

3 is greater than -5, -9, and -1.

Hint: Remember to distribute the negative when solving. A negative directly outside outside of and to the left the parenthesis times a negative number inside the parenthesis makes that number positive.

So for option B, you can simplify it to -3 +4 +2. And that equals 3.

A) -3+-4-(-2) = -5

B) -3-(-4)-(-2) = 3

C) -3+(-4)-2 = -9

D) -3-(-4)-2 = -1

8 0

3 years ago

Read 2 more answers