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e-lub [12.9K]
3 years ago
6

When you are on a roller coaster, you are constantly transforming from Potential to Kinetic energy and back. Explain how these e

nergy transformation would occur as the coaster goes from point A all the way to point E.

Physics
1 answer:
andreev551 [17]3 years ago
8 0

Answer:

The two types of energy possessed by the roller coaster are:

- Potential energy: it is the energy possessed by the roller coaster due to its position. It is calculated as

PE=mgh

where

m is the mass of the roller coaster

g is the acceleration due to gravity

h is the height of the roller coaster relative to the ground

- KInetic energy: it is the energy possessed by the roller coaster due to its motion. It is calculated as

KE=\frac{1}{2}mv^2

where

v is the speed of the roller coaster

Moreover, according to the law of conservation of energy, the total mechanical energy of the roller coaster (the sum of potential+kinetic energy) is constant during the motion:

E=PE+KE=const.

This implies that:

- When PE increases (because h increases), KE decreases (because v decreases)

- When PE decreases (because h decreases), KE increases (because v increases)

Now we can apply these conclusions to the motion of the roller coaster:

- When it moves from A to B, potential energy is converted into kinetic energy, so PE decreases and KE increases

- When it moves from B to C, kinetic energy is converted into potential energy, so PE increases and KE decreases

- When it moves from C to D, potential energy is converted into kinetic energy, so PE decreases and KE increases

- When it moves from D to E,  kinetic energy is converted into potential energy, so PE increases and KE decreases

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The complete question is;

Find the moment of inertia about each of the following axes for a rod that is 0.36 cm in diameter and 1.70m long, with a mass of 5.00 × 10 ^(−2) kg.

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Length; L = 1.7m

Mass;m = 5 × 10^(−2) kg

A) For an axis perpendicular to the rod and passing through its center, the formula for the moment of inertia is;

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B) For an axis perpendicular to the rod and passing through one end, the formula for the moment of inertia is;

I = mL²/3

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I = (5 × 10^(−2) × 1.7²)/3

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