Answer:

Explanation:
Since the cable touches the road at the mid point of two towers
so here we have vertex at that mid point taken to be origin
now the maximum height on the either side is given as

horizontal distance of the tower from mid point is given as

now from the equation of parabola we have



now we have

now we need to find the height at distance of 200 ft from center
so we have


Answer:
Time=8.23880597 seconds
Explanation:
Quantity of charge(q)=2.76c
Current(I)=0.335A
Time(t)=?
t=q/I
t=2.76/0.335
t=8.23880597seconds
to be franc i really think the answer is B
The velocity of the ball when it was caught is 12.52 m/s.
<em>"Your question is not complete it seems to be missing the following, information"</em>,
find the velocity of the ball when it was caught.
The given parameters;
maximum height above the ground reached by the ball, H = 38 m
height above the ground where the ball was caught, h = 30 m
The height traveled by the ball when it was caught is calculated as follows;
y = H - h
y = 38 - 30 = 8 m
The velocity of the ball when it was caught is calculated as;

Thus, the velocity of the ball when it was caught is 12.52 m/s.
Learn more here: brainly.com/question/14582703