What does X represent for this transmutation?

Where does the energy that causes evaporation come from?

MissTica

Im pretty sure its the sun.

Hope you have a grrreat day!

4 0

4 years ago

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15. What are the benefits to having a nuclear power plant nearby?

Svetlanka [38]

Low-cost energy. Although building nuclear power plants has a high initial cost, it's relatively cheap to produce energy from them and they have low operating costs.

Reliable.

Zero carbon emissions.

Promising future energy supply.

High energy density.

7 0

3 years ago

German physicist Werner Heisenberg related the uncertainty of an object\'s position (Δx) to the uncertainty in its velocity Δv.

Assoli18 [71]

Heisenberg's Uncertainty Principle gives a relationship between the standard deviation of an object's position and its momentum.

$\Delta p \cdot \Delta x = h / (4 \pi)$ where

$\Delta p$ the standard deviation of the object's momentum,
$\Delta x$ the standard deviation of the object's position, and
$h \approx 6.63 \times 10^{-34} \; \text{J} \cdot \text{s}$ the Planck's constant.

By definition, the momentum of the electron equals the product of its mass and velocity.

$p = m\cdot v$

Assuming that measurement of the mass of the electron $m$ is accurate. It is assumed to be a coefficient of constant value. The standard deviation in the electron's velocity is thus directly related to that of its mass. That is:

$\Delta p = m \cdot \Delta v$

$\Delta v = 0.01 \times 10^{6} \;\text{m}\cdot \text{s}^{-1}$ from the question;

$\Delta p = m\cdot v \\ \phantom{\Delta p} = 0.01 \times 10^{6} \; \text{m} \cdot \text{s}^{-1} \times 9.11 \times 10^{-31} \; \text{kg}\\\phantom{\Delta p} = 9.11 \times 10^{-27} \; \text{kg} \cdot \text{m}\cdot \text{s}^{-1}$

Convert the unit of the Planck's constant to base SI units (kg, m, s, etc.) if it was provided in derived units such as joules. Doing so would allow for a dimension analysis on the accuracy of the result.

$h = 6.63 \times 10^{-34} \; \text{J} \cdot \text{s}\\\phantom{h} = 6.63 \times 10^{-34} \; (\text{N}\cdot \text{m}) \cdot \text{s} \\\phantom{h} = 6.63 \times 10^{-34} \; ((\text{kg} \cdot \text{m}\cdot \text{s}^{-2}) \cdot \text{m}) \cdot \text{s}\\\phantom{h} = 6.63 \times 10^{-34} \; \text{kg} \cdot \text{m}^{2} \cdot \text{s}^{-1}$

Apply the Uncertainty Principle:

$\Delta x = h/ (4 \pi \cdot \Delta p)\\\phantom{\Delta x} = 6.63 \times 10^{-34} \; \text{kg} \cdot \text{m}^{2} \cdot \text{s}^{-1} / (4 \pi \cdot 9.11\times 10^{-27} \; \text{kg} \cdot \text{m}\cdot \text{s}^{-1})\\\phantom{\Delta x} = 5.79 \times 10^{-9} \; \text{m}$ .

Dimensional analysis:

$\Delta x$ resembles the standard deviation of a position measurement. It is expected to have a unit of meter, which is the same as that of position.

3 0

3 years ago

Which describes the relationship between [H+] and [OH−] ?

jarptica [38.1K]

For a neutral solution,
[H+][OH-] = 1 x 10⁻¹⁴

7 0

4 years ago

Iodine, I2, has many uses, including the production of dyes, antiseptics, photographic film, pharmaceuticals, and medicinal soap

svetoff [14.1K]

Answer:

2I ⁻ → I₂ + 2e⁻ describes the oxidation.

Cl₂ + 2e⁻ → 2Cl ⁻ describes the reduction.

Explanation:

Oxidation-reduction reaction is the simulaneous oxidation and reduction of the substances and is represented by two half-reactions.

The oxidation half-reaction is the loss of electrons, with the consequent increase in the oxidation state by the oxidized substance.

In this case, the process that shows the loss of electrons is:

2I⁻ → I₂ + 2e⁻

That reaction shows:

Two I⁻ ions lose two electrons (one each) to be oxidized to I₂.

The change in the oxidation number is from -1 to 0.

Hence this half-reaction is the oxidation reaction.

On the other hand, the reduction half-reaction is the gain of electrons, with the consequent reduction of the oxidation state by the reduced substance.

In this case, the process that shows the gain of electrons is:

Cl₂ + 2e⁻ → 2Cl⁻

That reaction shows:

Two Cl atoms gain two electrons (one each) to be reduced to Cl⁻.

The change in the oxidation number is from 0 to - 1.

Hence, this half-reaction is the reduction reaction.

Summary:

2I ⁻ → I₂ + 2e⁻ describes the oxidation.

Cl₂ + 2e⁻ → 2Cl ⁻ describes the reduction.

4 0

3 years ago