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Delvig [45]
3 years ago
9

What does X represent for this transmutation?

Chemistry
1 answer:
insens350 [35]3 years ago
6 0

Answer: 612C

Explanation: 49B + 24He —> 612C + 01n

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Calculate the ph of a 0.10 m solution of hypochlorous acid, hocl. ka of hocl is 3.5×10−8 at 25 ∘c. express your answer numerical
Viktor [21]

Answer:

4.23.

Explanation:

<em>∵ pH = - log[H⁺].</em>

<em>For weak acids:</em>

∵ [H⁺] = √(ka)(c).

∴ [H⁺] = √(3.5 × 10⁻⁸)(0.10 M) = 5.92 x 10⁻⁵.

∴ pH = - log[H⁺] = - log(5.92 x 10⁻⁵) = 4.2279 ≅ 4.23.

3 0
3 years ago
Joshua dissolved sugar in water to create a sugar solution. His friend Ray tells him it’s a compound, but Joshua corrects him. W
Lady_Fox [76]

the sugar disolved into the water so its a <u>mixture</u>. boom those words are it


5 0
3 years ago
Read 2 more answers
For an alloy that consists of 93.1 g copper, 111.7 g zinc, and 4.0 g lead, what are the concentrations of (a) Cu, (b) Zn, and (c
Andrew [12]

Answer:

(a) weight percent of Cu = 44.59%

(b) weight percent of Zn = 53.49%

(c) weight percent of Pb = 1.91%

Explanation:

Given: Alloy contains- Cu=93.1 g, Zn=111.7 g, Pb=4.0 g

Therefore, the total mass of the alloy (m) = mass of Cu (m₁) + mass of Zn (m₂)+ mass of Pb (m₃)

m= 93.1 g + 111.7 g + 4.0 g = 208.8 g

(a) weight percent of Cu = (m₁ ÷ m)× 100% =  (93.1 g ÷ 208.8 g)× 100% =44.59%

(b) weight percent of Zn = (m₂ ÷ m)× 100% =  (111.7 g ÷ 208.8 g)× 100% =53.49%

(c) weight percent of Pb = (m₃ ÷ m)× 100% =  (4.0 g ÷ 208.8 g)× 100% =1.91%

5 0
3 years ago
Use the following electron configuration given below to answer the following question.
NemiM [27]

Answer:

mental

Explanation:

the element is vanadium, it is a Transition metal

4 0
2 years ago
Determine the oxidation state of Cl in CIO3. A +3 B +7 C 0 D +1 E +5
Crazy boy [7]

Answer:

E.) +5

Explanation:

Oxygen always has -2 oxidation number.

Because there are 3 oxygen atoms present, this means oxygen is contributing a -6 charge (-2 x 3 = -6).

Therefore, since the overall molecule is -1, chlorine must have an oxidation number of +5 to cancel all of the negative charges but 1.

You can also think of the problem like an equation. In this equation, "x" is the oxidation number of chlorine, (-2) is the oxidation number of oxygen, (3) is the number of oxygen atoms present, and the equation is set equal to (-1) because that is the overall charge of the molecule.

x - 2(3) = -1

x - 6 = -1

x = 5

4 0
2 years ago
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