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3 years ago

I'm stuck on the blank space in the 3rd column anyone help thanks

Chemistry

1 answer:

Katen [24]3 years ago

8 0

B ⇒ bromine decolourises, cause its unsaturated hydrocarbon
C ⇒ no change, cause its saturated hydrocarbon

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The number of nitrogen atoms in one mole of nitrogen gas are...

9966 [12]

Explanation:

The number of nitrogen atoms in one mole of nitrogen gas are 6.02214179×1023 nitrogen atoms. 

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3 years ago

As the temperature of a gas in a closed container increases, what is true of the particles in the substance? (2 points)

Misha Larkins [42]

The rate of movement increases, as they get faster with more energy.

8 0

3 years ago

Read 2 more answers

NH3 + H2SO4 → __(NH4)2SO4

Zielflug [23.3K]

Answer:

This is not a balanced equation

Explanation:

Let's make it a balanced equation.

2 NH3 + H2So4 = (NH4)2So4

Glad I could help!!

8 0

3 years ago

Determine the boiling point of a 3.70 m solution of phenol in benzene. Benzene has a boiling point of 80.1°C and a boiling point

xeze [42]

Answer: The boiling point of a 3.70 m solution of phenol in benzene is $89.5^0C$

Explanation:

Elevation in boiling point:

$\Delta T_b=i\times k_b\times m$

where,

$\Delta T_b$ = change in boiling point

i= vant hoff factor = 1 (for benzene which is a non electrolyte )

$k_b$ = boiling point constant = $2.53^0C/kgmol$

m = molality = 3.70

$T_{solution}-T_{solvent}=i\times k_b\times m$

$T_{solution}-80.1^0C=1\times 2.53\times 3.70$

$T_{solution}=89.5^0C$

Thus the boiling point of a 3.70 m solution of phenol in benzene is $89.5^0C$

8 0

3 years ago

Find the number of grams in 16.95 mol hydrogen peroxide (H2O2). Round your

Feliz [49]

Answer: There are 576.46 number of grams present in 16.95 mol hydrogen peroxide $(H_{2}O_{2})$ .

Explanation:

Number of moles is defined as the mass of substance divided by its molar mass.

The molar mass of $H_{2}O_{2}$ is 34.01 g/mol. Hence, mass of hydrogen peroxide present in 16.95 moles is calculated as follows.

$Moles = \frac{mass}{molarmass}\\16.95 mol = \frac{mass}{34.01 g/mol}\\mass = 576.46 g$

Thus, we can conclude that there are 576.46 number of grams present in 16.95 mol hydrogen peroxide $(H_{2}O_{2})$ .

3 0

3 years ago