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k0ka [10]
3 years ago
14

Find the number of grams in 16.95 mol hydrogen peroxide (H2O2). Round your

Chemistry
1 answer:
Feliz [49]3 years ago
3 0

Answer: There are 576.46 number of grams present in 16.95 mol hydrogen peroxide (H_{2}O_{2}).

Explanation:

Number of moles is defined as the mass of substance divided by its molar mass.

The molar mass of H_{2}O_{2} is 34.01 g/mol. Hence, mass of hydrogen peroxide present in 16.95 moles is calculated as follows.

Moles = \frac{mass}{molarmass}\\16.95 mol = \frac{mass}{34.01 g/mol}\\mass = 576.46 g

Thus, we can conclude that there are 576.46 number of grams present in 16.95 mol hydrogen peroxide (H_{2}O_{2}).

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The maximum amount of nickel(II) cyanide that will dissolve in a 0.220 M nickel(II) nitrate solution is...?
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Answer : The maximum amount of nickel(II) cyanide is 5.84\times 10^{-12}M

Explanation :

The solubility equilibrium reaction will be:

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Initial conc.                        0.220       0

At eqm.                             (0.220+s)   2s

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