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3 years ago

Find the number of grams in 16.95 mol hydrogen peroxide (H2O2). Round your

Chemistry

1 answer:

Feliz [49]3 years ago

3 0

Answer: There are 576.46 number of grams present in 16.95 mol hydrogen peroxide $(H_{2}O_{2})$ .

Explanation:

Number of moles is defined as the mass of substance divided by its molar mass.

The molar mass of $H_{2}O_{2}$ is 34.01 g/mol. Hence, mass of hydrogen peroxide present in 16.95 moles is calculated as follows.

$Moles = \frac{mass}{molarmass}\\16.95 mol = \frac{mass}{34.01 g/mol}\\mass = 576.46 g$

Thus, we can conclude that there are 576.46 number of grams present in 16.95 mol hydrogen peroxide $(H_{2}O_{2})$ .

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Answer:

4.13 moles of Fe

Explanation:

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3 years ago

Find the ratio of speeds of an electron and a negative hydrogen ion (one having an extra electron) accelerated through the same

Tju [1.3M]

Answer:

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Explanation:

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3 years ago

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Vsevolod [243]

1 mole of any substance has Avagadro number of molecules and it's weight is equal to its molecular weight.
.......................................................................................................................
Answer 1:
Molecular weight of HNO3 = 63.01 g/mol

Therefore, 1mole of HNO3 = 63.03 g
Hence, 15.7 mole of HNO3 = 63.03 X 15.7
= 989.57 g

Thus, mass of 15.7 mole of HNO3 = 989.57 g
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Answer 2:
Molecular weight of H2O2 = 34.01 g/mol

Therefore, 1mole of H2O2 = 34.01g
Hence, 0.00104 mole of H2O2 = 34.01 X 0.00104
= 0.03537 g

Thus, mass of 0.00104 mole of H2O2 is 0.03537 g
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Answer 3:
Molecular weight of SO2 = 64.07 g/mol

Therefore, 1mole of SO2 = 64.07 g
Hence, 72.1 mmole of SO2 = 64.07 X 0.0721
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Thus, mass of 72.1 mm of SO2 is 4.619 g
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Answer 4:
Molecular weight of XeF2 = 169.29 g/mol

Therefore, 1mole of XeF2 = 169.29 g
Hence, 1.23 mole of XeF2 = 169.29 X 1.23
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Thus, mass of 1.23 mole of XeF2 is 208.23 g

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4 years ago