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k0ka [10]
3 years ago
14

Find the number of grams in 16.95 mol hydrogen peroxide (H2O2). Round your

Chemistry
1 answer:
Feliz [49]3 years ago
3 0

Answer: There are 576.46 number of grams present in 16.95 mol hydrogen peroxide (H_{2}O_{2}).

Explanation:

Number of moles is defined as the mass of substance divided by its molar mass.

The molar mass of H_{2}O_{2} is 34.01 g/mol. Hence, mass of hydrogen peroxide present in 16.95 moles is calculated as follows.

Moles = \frac{mass}{molarmass}\\16.95 mol = \frac{mass}{34.01 g/mol}\\mass = 576.46 g

Thus, we can conclude that there are 576.46 number of grams present in 16.95 mol hydrogen peroxide (H_{2}O_{2}).

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____ is the amount of matter in an object. Question 1 options: Matter Gravitational Pull Mass Weight
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Name one of the new products formed when acids and alkalis mix?
Kruka [31]

Answer:

Water (H20)

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2 years ago
How are solubility and temperature generally related in a system consisting of a solid solute and a liquid solvent?
Nesterboy [21]

Solubility and temperatures are directly related. The higher the temperature of the solvent, the higher the solubility of the solute in the solvent.

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8 0
3 years ago
Show the calculation of the molar mass (molecular weight) of a solute if a solution of 5.8 grams of the solute in 100 grams of w
Leni [432]

Answer : The molar mass of solute is, 89.9 g/mol

Explanation : Given,

Mass of solute = 5.8 g

Mass of solvent (water) = 100 g

Formula used :  

\Delta T_f=K_f\times m\\\\T_f^o-T_f=T_f\times\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of water}}

where,

\Delta T_f = change in freezing point

T_f^o = temperature of pure solvent (water) = 0^oC

T_f = temperature of solution = 1.20^oC

K_f = freezing point constant of water = 1.86^oC/m

m = molality

Now put all the given values in this formula, we get

(0^oC)-(1.20^oC)=1.86^oC/m\times \frac{5.8g\times 1000}{\text{Molar mass of solute}\times 100g}

\text{Molar mass of solute}=89.9g/mol

Therefore, the molar mass of solute is, 89.9 g/mol

5 0
3 years ago
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