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3 years ago

PLEASE HELP ME WITH ATOMS AND DALTON I BEG YOU

Chemistry

1 answer:

rosijanka [135]3 years ago

6 0

Dalton's atomic theory was the first complete attempt to describe all matter in terms of atoms and their properties.

Dalton based his theory on the law of conservation of mass and the law of constant composition.

The first part of his theory states that all matter is made of atoms, which are indivisible.

The second part of the theory says all atoms of a given element are identical in mass and properties.

The third part says compounds are combinations of two or more different types of atoms.

The fourth part of the theory states that a chemical reaction is a rearrangement of atoms.

Parts of the theory had to be modified based on the discovery of subatomic particles and isotopes.

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How many Available electrons does CIO3, chlorate ion?

Natalija [7]

For, ClO3- there are 26 valence electrons, so total pairs of electrons are 13.

6 0

3 years ago

If 9.2 g of calcium react completely with excess aluminum chloride how many grams of aluminum would be produced?

Gekata [30.6K]

Explanation:

3Ca(s) + 2AlCl3(aq) -> 3CaCl2(aq) + 2Al(s)

According to the question, Ca is the limiting reactant.

Therefore, we equate Ca to Aluminium which is the product whose mass we want to find

Molar mass of Ca- 40g/mol

". ". of Al- 27g/mol

3Ca --> 2Al

3×40 --> 2×27

9.2 --> x

x = 9.2×2×27= 496.8÷120=4.14

8 0

3 years ago

Answer ASAP Please this is a timed test

DiKsa [7]

you want to design a faster car

because thats engineering

○○○

testing evaporation is not engineering

and making slime isnt either...

lets say it like this do you use a wrench for slime or evaporation?

nope but you do for cars

♥

7 0

3 years ago

A mixture contains only NaCl and Al2(SO4)3. A 1.45-g sample of the mixture is dissolved in water, and an ex- cess of NaOH is add

chubhunter [2.5K]

Answer:

The mass percent of aluminum sulfate in the sample is 16.18%.

Explanation:

Mass of the sample = 1.45 g

$Al_2SO_3+6NaOH\rightarrow 2Al(OH)_3+3Na_2SO_4$

Mass of the precipitate = 0.107 g

Moles of aluminum hydroxide = $\frac{0.107 g}{78 g/mol}=0.001372 mol$

According to reaction, 2 moles of aluminum hydroxide is obtained from 1 mole of aluminum sulfate .

Then 0.001372 moles of aluminum hydroxide will be obtained from:

$\frac{1}{2}\times 0.001372 mol=0.000686 mol$

Mass of 0.000686 moles of aluminum sulfate :

= 0.000686 mol × 342 g/mol = 0.2346 g

The mass percent of aluminum sulfate in the sample:

$=\frac{ 0.2346 g}{1.45g}\times 100=16.18\%$

5 0

3 years ago

Help please and thank you for who ever

Korolek [52]

Answer:the first one

Explanation:

7 0

3 years ago

Read 2 more answers