3 years ago

WILL GIVE BRAINLIEST!! 6, 7 & 8 PLEASE!!!

Physics

1 answer:

Troyanec [42]3 years ago

5 0

6 is between 3 and 4 or 3.5 7 is 7.5 and 8 is buggy 1 will win and buggy 1 will have to wait 31.5

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A proton is placed in an electric field of intensity 700 N/C. What are the magnitude and direction of the acceleration of this p

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Answer:

Acceleration of proton will be $a=0.67\times 10^{11}m/sec^2$

Explanation:

We have given a proton is placed in an electric field of intensity of 700 N/C

So electric field E = 700 N/C

Mass of proton $m=1.67\times 10^{-27}kg$

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According to newton's law force is given by F = ma

So $1.67\times 10^{-27}\times a=1.120\times 10^{-16}$

$a=0.67\times 10^{11}m/sec^2$

So acceleration of proton will be $a=0.67\times 10^{11}m/sec^2$

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Hope I helped!
~Mathlete12321

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