A ball is projected at an angle of 30° above the horizontal with a speed of 35 m/s.What will be its approximate horizontal range
2 answers:
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Answer:
The acceleration is 3.16x10¹⁷ m/s².
Explanation:
First, we need to find the magnitude of the Coulombs force (F):
<u>Where</u>:
K is the Coulomb constant = 9x10⁹ Nm²/C²
q₁ is the charge = 20x10⁻⁹ C
q₂ is the electron's charge = -1.6x10⁻¹⁹ C
d is the distance = 1.0 cm = 1.0x10⁻² m
Now, we can find the acceleration:
Therefore, the acceleration is 3.16x10¹⁷ m/s².
I hope it helps you!
Answer:
a. 25m
b. 25m
c. 35m
Explanation:
Given the distances walked as 15m east and 20m north:
Using Pythagoras Theorem, we calculate displacement as:
Hence, the resultant displacement is 25m
b. The distance from her start point is obtained by drawing a straight line from her final point to her initial point.
Given the distances walked as 15m east and 20m north:
Using Pythagoras Theorem, we calculate displacement as:
Hence, she is 25m away from her starting point.
c. The distance traveled is calculated by summing the total distance walked:
Hence, the total distance traveled is 35m