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Luba_88 [7]
3 years ago
13

What is the balance equation for _AI+_Pb(NO3)2—__Pb+__Ca(NO3)2

Chemistry
1 answer:
Firdavs [7]3 years ago
4 0

Answer:

2 Al + 3 Pb(NO3)2 > 2 Al(NO3)3 + 3 Pb

Explanation:

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A lime has a [H+] concentration of 0.0120 M.<br><br> What is the pH of the lime? 3 sig figs
Novosadov [1.4K]

Answer: pH= 1.92

Explanation:

pH= -log[H+]

pH= -log[0.012]

= 1.92

4 0
3 years ago
A balloon is filled to a volume of 1.50 L with 3.00 moles of gas at 25 °C. With pressure and temperature held constant, what wil
Ludmilka [50]

Answer:

Volume : 1.25 L

Explanation:

We are given here that the volume ( V_1 ) = 1.50 Liters, the initial moles ( held at 25 °C ) = 3.00 mol, and the final moles ( n_2 ) = 3.00 - 0.5 = 2.5 mol. The final mol is calculated given that 0.50 mol of gas are released from the prior 3.00 moles of gas.

Volume ( V_1 ) = 1.50 L,

Initial moles ( n_1 ) = 3.00 mol,

Final Volume ( n_2 ) = 3.00 - 0.5 = 2.5 mol

Applying the combined gas law, we can calculate the final volume ( V_2 ).

P_1V_1 / n_1T_1 = P_2V_2 / n_2T_2 - we know that the pressure and temperature are constant, and therefore we can apply the following formula,

V_1 / n_1 = V_2 / n_2 - isolate V_2,

V_2 = V_1 n_2 / n_1 = 1.50 L * 2.5 mol / 3.00 mol = ( 1.5 * 2.5 / 3 ) L = 1.25 L

The volume of the balloon will be 1.25 L.

6 0
4 years ago
50 points!! Brainliest if correct!!
Luda [366]

The answer is C. The answer is C because if u increase the surface area, the more reactants u will get. and if u get more The reactants will move faster. Hoped that Helped!:-)

4 0
3 years ago
How many atoms of phosphorus are in 3.80 mol of copper(II) phosphate?
Sladkaya [172]
Wouldn't you take Avogadro' number and multiply by 3.80 maybe
6 0
3 years ago
What is the balanced equation for the combustion of magnesium?
Lostsunrise [7]

Answer:

2Mg  +  O2 →  2MgO

Explanation:

In all conbustion you should know, that reactans are an specific compound and O2, so the products must be CO2 and H2O, or in this case, the corresponding oxide.

6 0
3 years ago
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