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AveGali [126]
3 years ago
8

If the current in a wire of a cd player is 12.0 ma, how long would it take for 6.50 c of charge to pass a point in this wire? an

swer in units of s.
Physics
1 answer:
Galina-37 [17]3 years ago
6 0
The current intensity is defined as the amount of charge Q that passes through a certain point of an electrical wire in a time interval of \Delta t:
I= \frac{Q}{\Delta t}

In our problem, the current intensity is
I=12.0 mA=0.012 A
while the amount of charge that passes a certain point of the wire is 
Q=6.50 C

If we re-arrange the previous equation:
\Delta t= \frac{Q}{I}
we can find the time needed for this amount of charge to pass through a point of the wire:
\Delta t= \frac{6.50 C}{0.012 A} =541.7 s
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In the nuclear fission process mass is converted into energy. Determine the total mass that must be converted to energy in one y
brilliants [131]

Answer:

1) Mass that needs to be converted at 100% efficiency is 0.3504 kg

2) Mass that needs to be converted at 30% efficiency is 1.168 kg

Explanation:

By the principle of mass energy equivalence we have

E=mc^{2}

where,

'E' is the energy produced

'm' is the mass consumed

'c' is the velocity of light in free space

Now the energy produced by the reactor in 1 year equals

Energy=Power\times time\\\\\therefore Energy=1\times 10^{9}\times 365\times 24\times 3600\\\\Energy=31.536\times 10^{15}Joules

Thus the mass that is covertred at 100% efficiency is

mass=\frac{Energy}{c^{2}}\\\\mass=\frac{31.536\times 10^{15}}{(3\times 10^{8})^{2}}\\\\mass=\frac{31.536\times 10^{15}}{9\times 10^{16}}\\\\\therefore mass=0.3504kg

Part 2)

At 30% efficiency the mass converted equals

mass|_{30}=\frac{mass|_{100}}{0.3}\\\\mass|_{30}=\frac{0.3504}{0.3}\\\\mass|_{30}=1.168kg

8 0
3 years ago
Heat energy can be transferred from a source to a receiver by I. radiation. II. convection. III. conduction. A.
nadya68 [22]
It can be transferred by I, II, and III




Hope this helps ! :}
7 0
3 years ago
Read 2 more answers
You stand17.5 m from a wall holding a baseball. You throw the baseball at the wall at an angle of 20.5∘ from the ground with an
Lelechka [254]

Answer: 8.8 m

Explanation:

The movement of the baseball to the wall is a example of parabolic motion. While the baseball aproach the wall it is affected by gravity.

In this case, because the Initial Velocity of the ball is a vecotr, it can be defined using its two directionals compounds. One, on the Y-axis and another on the X-axis. This can be related, on how a hypotenuse is the product of two legs of the triangle. Because of this, each one of this, can be know using the following equation:

Vx = Vo * cos(∅)

Vy = Vo * sin(∅)

Where Vo is the initial velocity 27.5 m/s, and ∅ is the angle which is 20.5°. So we calculate:

Vx = 27.5m/s * cos(20.5)

Vx = 27.5m/s * 0.936

Vx = 25.74m/s

Vy = 27.5m/s  * sin(20.5)

Vy = 27.5m/s * sin(20.5)

Vy = 9.62m/s

Now the movement is divided on two parts, one under the effect of gravity and another one with a constant velocity.

To know how tall does the baseball hit the wall, we need to know first how much time it takes the ball to reach the wall on the X-axis. The wall is 17.5m away, we velocity on Vx that is constant we can calculate as it follow:

Time (T) = Distance (D) / Velocity (V)

Where Distance is 17.5m and our Velocity is the Vx calculated before.

T = 17.5 m / 25.74m/s

T = 0.68s

This is the time it takes the ball to reach the wall.

Know with the time, we can calculate the how tall it got on that time with the following equation:

x = (Vo*t) + (\frac{1}{2} *a*t^{2} )

Where Vo is the Y-Compound of the Initial Velocity.

a is the aceleration, in this case the Gravity. Which, will be negative because is oposing the movement. Gravity is equal to 9.81 m/s^{2}

And t is the time it takes the ball to get to the wall.

x = (Vy*T) + (\frac{1}{2} *g*T^{2} )

x = ((9.62m/s)*0.68s) + (\frac{1}{2} *(9.81m/s^{2})*(0.68s)^{2} )

x = 8.8 m

This is the height that the baseball touch the wall.

6 0
3 years ago
A charge of 6.7 × 10^-15 coulombs is located at a point where its potential energy is 5.6 × 10^-12 joules. What is the electric
natita [175]

Answer:

C. 8.4 × 10^2 volts

Explanation:

The potential energy of a charge is given by:

U=qV

where

q is the magnitude of the charge

V is the electric potential

In this problem, we have

q=6.7\cdot 10^{-15} C is the charge

U=5.6\cdot 10^{-12} J is the potential energy

Re-arranging the formula and using these numbers, we can find the electric potential:

V=\frac{U}{q}=\frac{5.6\cdot 10^{-12} J}{6.7\cdot 10^{-15} C}=835.8 V = 8.4\cdot 10^2 V

4 0
3 years ago
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Jody does long distance running and also strength trains twice a week.
murzikaleks [220]

<u>Answer:</u>

<em>Jody will have strong bones and show muscle hypertrophy. </em>

<u>Explanation:</u>

Long distance running practiced regularly helps in <em>increasing the strength of bones</em>. Muscular hypertrophy is the increase in mass of skeletal muscles due to the increase in the size of myofibrils or increase in muscle glycogen storage. <em>Strength training exercises</em> performed regularly induce muscular hypertrophy.

During strength <em>training exercises muscles</em> undergo contraction and repeated contraction breaks muscle fibres. New muscle fibres are added as a means of repair and this happens at the relaxing phase of muscles. More muscle fibres are added to <em>compensate the damage and thus muscle mass increases. </em>

6 0
3 years ago
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