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Bumek [7]
3 years ago
11

When stated as a percentage, the useful energy transferred by a device divided by the total energy supplied to the device is kno

wn as the device's __________. What one word completes the sentence?
Physics
1 answer:
Verdich [7]3 years ago
4 0

Efficiency

Explanation:

Efficiency is a ratio/percentage that is useful in comparing the energy transferred by a device to the total energy supplied to it.

  Percentage efficiency = \frac{energy input}{total energy supplied} x 100

  • As with most system, none is 100% efficient.
  • During energy is transferred some are lost and only a little portion is used in doing actual work by the machine.
  • This validates the third law of thermodynamics which proposes that no system is 100% efficient.
  • A 100% efficiency implies total energy input is used doing all the work.
  • This is impossible. The bulk of the energy goes into heating the system.

learn more:

Third law of thermodynamics brainly.com/question/3564634

#learnwithBrainly

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A standard basketball (mass = 624 grams; 24.3 cm in diameter) is held fully under water. a. Calculate the buoyant force and weig
galina1969 [7]

Answer:

Explanation:

Mass = 624 gm = .624 kg

weight = .624 x 9.8

= 6.11 N

Radius of ball = 12.15 x 10⁻² cm

volume of ball

= 4/3 x 3.14 x ( 12.15 x 10⁻²)³

= 7509.26 x 10⁻⁶ m³

Buoyant force = weight of displaced water

= 7509.26 x 10⁻⁶ x 10³ x 9.8

= 73.59 N

b ) Since buoyant force exceeds the weight of the ball , it will float .

c )

Let volume v sticks out while floating .

Volume under water

= 7509.26 x 10⁻⁶ - v

its weight

= (7509.26 x 10⁻⁶ - v ) x 10³ x 9.8

For floating

(7509.26 x 10⁻⁶ - v ) x 10³ x 9.8  =  .624 x 9.8 ( weight of ball )

(7509.26 x 10⁻⁶ - v ) x 10³ = .624

7.509 - v x 10³ = .624

v x 10³ = 7.509 - .624

v x 10³ = 6.885

v = 6.885 x 10⁻³ m³

fraction

= v / total volume

=  6.885 x 10⁻³ / 7.51 x 10⁻³

91.67 %

8 0
3 years ago
A string with a mass of 0.034 kg has a length of 4.80 m. If the tension in the string is 100.00 N and a sinusoidal wave with an
GaryK [48]

Explanation:

Below is an attachment containing the solution.

4 0
3 years ago
You have a gold nugget and find its mass to be 25 grams. How much volume does this gold nugget occupy?
Kay [80]

According to the solving, the volume that this gold nugget occupies is 1.29 cm³.

<h3>What is volume?</h3>

Volume is a standard measure of three-dimensional space that is occupied. It is typically mathematically represented using standard or SI-derived units. Volume and the concept of length are connected. It is sometimes referred to as the object's capacity.

d= m/ V

m=  dV

V= m/d

<h3>So according to the given data,</h3>

The mass of the gold nugget is 25 grams.

The density of gold is 19.32 g/cm³.

We know that,

m= Vd

To find out the Volume(V),

V= m/d

V= (25 g)/(19.32 g/cm³)

V= 1.29 cm³.

According to the solving, the volume this gold nugget occupies is 1.29cm³.

To know more about questions of volume visit,

brainly.com/question/1578538

#SPJ1

8 0
1 year ago
A 1.6-cm-thick wood floor covers a 4.0m×5.5m room. Part A The subfloor on which the flooring sits is at a temperature of 16.1 ∘C
Bogdan [553]

Answer:

Rate of heat conduction will be 935 Watt

Explanation:

We have given thickness of the floor d = 1.6 cm = 0.016 m

Area A=4\times 5.5=22m^2

Temperature difference \Delta T=19.5-16.1=3.4^{\circ}C

Thermal conductivity of the wood k = 0.200 w/M-K

We have to find heat conduction

Heat conduction is given by \frac{Q}{t}=\frac{kA\Delta T}{d}=\frac{0.200\times 22\times 3.4}{0.016}=935Watt

Rate of heat conduction will be 935 Watt

3 0
4 years ago
Given that the CFL bulb is rated at 10% efficiency, if the LED bulb consumes half the amount of electrical power, for the same a
Butoxors [25]

Answer and explanation:

The efficiency of the LED bulb is 20% while The efficiency of the Inc bulb is 1%.

The lightbulb efficiency can be defined as the quotient between the amount of usable light and the amount of electrical power output. For the efficiency of the CFL Bulb:

\epsilon_{CFL}=\frac{L_0}{P_0}=0.1

Therefore:

\epsilon_{led}=\frac{L_0}{0.5P_0}=2 \cdot0.1=0.2\\\epsilon_{INC}=\frac{L_0}{10P_0}=0.1 \cdot 0.1=0.01

4 0
3 years ago
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