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Elanso [62]
3 years ago
14

What is the best explanation for how the plates move?

Physics
1 answer:
miskamm [114]3 years ago
3 0

Answer:

Explanation:

Some geologists favor convection currents in the mantle as the best explanation for plate tectonic movement. It is reasonable to assume that the heat radiated from the core creates convection currents in the mantle, and the mantle rocks begin to move plastically.

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Push a notebook or some other object so that it slides across a table or desktop. What force causes the notebook to start moving
Tju [1.3M]

Answer:

Kinetic force

Explanation:

7 0
3 years ago
A hiker leaves her camp and walks 3.5 km in a direction of 55° south of west to the lake. after a short rest at the lake, she hi
3241004551 [841]

Let's choose east as positive x-direction and south as positive y-direction. We can resolve the two displacement along these two axes:

- Displacement 1 (3.5 km, 55^{\circ} south of west

d_{1x}=-(3.5 km)( cos 55^{\circ})=-2.01 km

d_{1y}=(3.5 km)( sin 55^{\circ})=2.87 km

- Displacement 2 (2.7 km, 16^{\circ} east of south

d_{2x}=(2.7 km)( sin 16^{\circ})=0.74 km

d_{1y}=(2.7 km)( cos 16^{\circ})=2.60 km

So, the total components on the two directions are

d_x = -2.01 km+0.74 km=-1.27 km

d_y=2.87 km+2.60 km=5.47 km

And the magnitude of the hiker's resultant displacement is

d=\sqrt{(1.27 km)^2+(5.47 km)^2}=5.6 km

8 0
3 years ago
Read 2 more answers
Although 0 dB is often referred to as the lower threshold of human hearing, it is important to realize that the human ear is not
IRISSAK [1]

Answer:

20 Hz

15.8 times

Explanation:

A

Although the range of frequency for any human's ear is usually said to be between 20 Hz and 20 kHz. And since the question asked for the least intense frequency, that has to be 20 Hz. Essentially the frequency most people perceive the least intense sound is 20 Hz.

B

A 100-Hz sound must be 10^1.2 times or 15.8 times more intense compared to a 1000-Hz sound to be perceived as equal to 60 phons of loudness

5 0
3 years ago
calculate speed and velocity of the following. the race car was moving for 3.7 hours and during that time it traveled a distance
Ksju [112]

Answer:

v = 135.13 mph

Explanation:

Given that,

The race car was moving for 3.7 hours and during that time it traveled a distance of 500 miles south.

We need to find the speed of the car.

We know that,

Speed = distance/time

So,

v=\dfrac{500\ miles}{3.7\ h}\\\\v=135.13\ mph

So, the speed of the car is equal to 135.13 mph.

7 0
3 years ago
An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.50 mm. A 25
torisob [31]

Answer:

The electric field is 16666.66 V/m.

The surface charge density is 1.474\times10^{-7}\ C/m^2

The capacitance is 4.484\times10^{-12}\ F

The charge on each plate is 112.1\times10^{-12}\ C

Explanation:

Given that,

Area =7.70 cm²

Distance = 1.50 mm

Potential difference = 25.0 V

Suppose  we find the electric field between the plates, the surface charge density, the capacitance and the charge on each plates.

We need to calculate the electric field

Using formula of electric field

E=\dfrac{V}{d}

Put the value into the formula

E=\dfrac{25.0}{1.50\times10^{-3}}

E=16666.66\ V/m

We need to calculate the charge density

Using formula of charge density

\sigma=E\times\epsilon_{0}

Put the value into the formula

\sigma=16666.66\times8.85\times10^{-12}

\sigma=1.474\times10^{-7}\ C/m^2

We need to calculate the capacitance

Using formula of capacitance

C=\dfrac{\epsilon_{0}A}{d}

Put the value into the formula

C=\dfrac{8.85\times10^{-12}\times7.60\times10^{-4}}{1.50\times10^{-3}}

C=4.484\times10^{-12}\ F

We need to calculate the charge

Using formula of charge

q=CV

Put the value into the formula

q=4.484\times10^{-12}\times25.0

q=112.1\times10^{-12}\ C

Hence, The electric field is 16666.66 V/m.

The surface charge density is 1.474\times10^{-7}\ C/m^2

The capacitance is 4.484\times10^{-12}\ F

The charge on each plate is 112.1\times10^{-12}\ C

8 0
3 years ago
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