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Elanso [62]
3 years ago
14

What is the best explanation for how the plates move?

Physics
1 answer:
miskamm [114]3 years ago
3 0

Answer:

Explanation:

Some geologists favor convection currents in the mantle as the best explanation for plate tectonic movement. It is reasonable to assume that the heat radiated from the core creates convection currents in the mantle, and the mantle rocks begin to move plastically.

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The atmospheric pressure at the surface of titan is.
Harrizon [31]

Answer:

about 1.5 bars

Titan's atmosphere is similar to Earth's both in the predominance of nitrogen gas and in surface pressure, which is about 1.5 bars, or 50 percent higher than sea-level pressure on Earth.

Explanation:

8 0
1 year ago
The Drude model uses Newton’s laws, which say that an electron in a constant electric field should experience constant accelerat
Troyanec [42]

Answer:

Electrons are influenced by internal forces.

-On the temperature, density of electrons per unit of volume and relaxation time.

-The temperature

Explanation:

The Drude model neglects interactions between electrons and ions and with themselves. Those interactions (by which we refer as electromagnetic forces) influence in the random movement and freedom of the electron. So, they could be more restricted or could influence in conductivity more.

The deduction of the resistivity comes from the Ohm's law, which states that the Electric field in the material is proportional to the current density of electrons by a constant, which is the resistivity itself. The equation goes as follows:

\rho=\frac{m_e}{e^2n_e \tau }

Where e refers to electron (or the charge of it), τ is the relaxation time (average time between collisions), m is the mass and n is the density of charges (electrons in this case) per volume. However, experimentally resistivity is also dependent on temperature, which actually influence the relaxation time. The thermal energy influence in the behavior of the electrons, making them collide with phonons, have more randomness and reduced mean free path.

6 0
3 years ago
The process of mitosis makes body cells which are also called_______ cells.<br> NEED DONE ASAP!!!!!
lubasha [3.4K]

Answer:

daughters cells

Explanation:

when people refer to “cell division,” they mean mitosis, the process of making new body cells. Meiosis is the type of cell division that creates egg and sperm cells. Mitosis is a type of cell division in which one cell (the mother) divides to produce two new cells (the daughters) that are genetically identical to itself.

4 0
2 years ago
Read 2 more answers
How is most of the electricity we use at home generated?
Sveta_85 [38]
Nuclear power plants, wind farms, water farms, and geothermal heating
3 0
3 years ago
On August 10, 1972, a large meteorite skipped across the atmosphere above the western United States and western Canada, much lik
Anon25 [30]

a) 4.62\cdot 10^{14} J

b) 0.110 megatons

c) 8.46 bombs

Explanation:

a)

The energy lost by the meteorite is equal to the difference between its final kinetic energy and its initial kinetic energy:

\Delta K=K_f-K_i

Which can be rewritten as:

\Delta K=\frac{1}{2}mv^2-\frac{1}{2}mu^2

where:

m=3.2\cdot 10^6 kg is the mass of the meteorite

v=0 is the final speed of the meteorite

u=17 km/s = 17,000 m/s is the initial speed of the meteorite

Substituting the values into the equation, we found the loss in energy of the meteorite:

\Delta K=0-\frac{1}{2}(3.2\cdot 10^6)(17000)^2=-4.62\cdot 10^{14} J

So, the energy lost by the meteorite is 4.62\cdot 10^{14} J

b)

The energy equivalent to 1 megaton of TNT is

E_{TNT}=4.2\cdot 10^{15} J

Here the energy lost by the meteorite is

E=4.62\cdot 10^{14} J

Therefore, in order to write the energy lost by the meteorite as a multiple of the energy of 1 megaton of TNT, we have to divide the energy lost by the meteorite by the energy equivalent to 1 TNT; we find:

\frac{E}{E_{TNT}}=\frac{4.62\cdot 10^{14}}{4.2\cdot 10^{15}}=0.110

So, the energy lost by the meteorite corresponds to 0.110 megatons.

c)

The energy of one atomic bomb explosion in Hiroshima is equal to

E'=13 kt (13 kilotons)

which corresponds to

E'=0.013 Mt (0.013 megatons)

Here the energy of the meteorite is equal to

E=0.110 Mt (0.110 megatons)

Therefore, we can find how many Hiroshima bombs are equivalent to teh meteorite impact by using the following rules of three:

\frac{1 bomb}{0.013 Mt}=\frac{x bombs}{0.110 Mt}\\x=\frac{1\cdot 0.110}{0.013}=8.46

So, 8.46 bombs.

5 0
3 years ago
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