All categories

4 years ago

What is the Bronsted acid in the following equation HBr+H20 H30+ + Br-

Chemistry

1 answer:

Natali [406]4 years ago

3 0

Answer:HBr

Explanation:According to Bronsted Lowry, an acid is a proton donor while a base is a proton acceptor.

HBr donates a proton H+ to H20 thereby resulting in the product H30+ + Br-

You might be interested in

The energy required to ionize a mole of potassium ions is 419 kJ/mol . What is the longest wavelength of light capable of this i

liraira [26]

First divide the ionization energy by Avogadro's number to get the energy per atom of potassium;
419 kj/mol / 6.023 x 10²³
= 4.19 x 10⁵ / 6.023 x 10²³ = 6.96 x 10⁻¹⁹
E = hc/λ
where lambda (λ) is the wavelength, h is Planck's constant, c is the speed of light
E = 6.96 x 10⁻¹⁹ j/atom
h =6.63x10⁻³⁴ Js
c = 3 x 10⁸ m/s
λ = ?
λ = hc/E = (6.63x10⁻³⁴ x 3 x 10⁸ ) / 6.96 x 10⁻¹⁹ = 285.8nm = 286nm
The longest wavelength of light capable of this ionization is 286nm.

3 0

3 years ago

What is the voltage of the voltaic cell Zn|Zn2+||Cu2+|Cu at 298 K if [Zn2+] = 0.2 M and [Cu2+] = 4.0 M? Cu2+ + 2e- → Cu Eo = +0.

OLga [1]

Answer : The voltage of the voltaic cell is 1.14 V

Explanation :

From the given cell representation, we conclude that

The copper will undergo reduction reaction will get reduced. Zinc will undergo oxidation reaction and will get oxidized.

The oxidation-reduction half cell reaction will be,

Oxidation half reaction: $Zn\rightarrow Zn^{2+}+2e^-$

Reduction half reaction: $Cu^{2+}+2e^-\rightarrow Cu$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode. That means, gold shows reduction and occurs at cathode and chromium shows oxidation and occurs at anode.

The overall balanced equation of the cell is,

$Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu$

To calculate the $E^o{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

$E^o_{cell}=E^o_{(Cu^{2+}/Cu)}-E^o_{(Zn^{2+}/Zn)}$

Putting values in above equation, we get:

$E^o_{cell}=(+0.34V)-(-0.76V)$

$E^o_{cell}=1.1V$

Now we have to calculate the emf or voltage of the cell.

Using Nernest equation at 298 K :

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}]}{[Cu^{2+}]}$

where,

n = number of electrons in oxidation-reduction reaction = 2

$E_{cell}$ = ?

Now put all the given values in the above equation, we get:

$E_{cell}=1.1-\frac{0.0592}{2}\log \frac{0.2}{4.0}$

$E_{cell}=1.14V$

Therefore, the voltage of the voltaic cell is 1.14 V

5 0

3 years ago

What occurs to the atoms of reactants in a chemical reaction?

djyliett [7]

Question:

What occurs to the atoms of reactants in a chemical reaction?

Answer:

In a chemical reaction, the atoms and molecules that interact with each other are called reactants. ... No new atoms are created, and no atoms are destroyed. In a chemical reaction, reactants contact each other, bonds between atoms in the reactants are broken, and atoms rearrange and form new bonds to make the products.

6 0

3 years ago

What do sodium and magnesium have in common?

lara [203]

Answer:

daddy will help

Explanation:

uhhhhhhhhhhhhhhhhhhh

7 0

3 years ago

Which career field is an applied science? Which hypothesis is testable?

VashaNatasha [74]

Chemists, biologist, pharmacist, medical researcher ect…

4 0

3 years ago