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Sever21 [200]
3 years ago
14

How do gut bacteria help people?(1 point)

Chemistry
2 answers:
lakkis [162]3 years ago
7 0
By making enzymes to break down food
Fiesta28 [93]3 years ago
3 0

Answer: A) by making enzymes to break down food.

Hope this helps!

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Can you explain what makes Earth habitable using science vocabulary words system & planetary geologist
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Earth is the right distance from the sun. It’s protected from harmful solar radiation by its magnetic field and the atmosphere keeps it warm. Earth contains the right chemical ingredients to sustain life such as H2O (water) and C (carbon)
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5 1 2 4and 3 this is correct way

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What is an energy transformation?
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Energy is invisible yet it's all around us and throughout the universe. Energy can never be made or destroyed, but its form can be converted and changed.
While energy can be transferred or transformed, the total amount of energy does not change – this is called energy conservation.
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4 0
3 years ago
Which atom has five electrons in its outer level and 10 electrons in the inner energy levels
Sever21 [200]

Oxygen 47 Hydrogen 63

Silicon 28 Oxygen 25.5

Aluminum 7.9 Carbon 9.5

Iron 4.5 Nitrogen 1.4

Calcium 3.5 Calcium 0.31

Sodium 2.5 Phosphorus 0.22

Potassium 2.5 Chlorine 0.03

Magnesium 2.2 Potassium 0.06

Titanium 0.46 Sulfur 0.05

Hydrogen 0.22 Sodium 0.03

Carbon 0.19 Magnesium 0.01

All others <0.1 All others <0.01 Living matter

6 0
3 years ago
Chlorine atoms react with methane, forming HCl and CH3. The rate constant for the reaction was determined to be 3.600×107 at 278
Ratling [72]

<u>Answer:</u> The activation energy for the reaction is 40.143 kJ/mol

<u>Explanation:</u>

To calculate activation energy of the reaction, we use Arrhenius equation for two different temperatures, which is:

\ln(\frac{K_{317K}}{K_{278K}})=\frac{E_a}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_{317K} = equilibrium constant at 317 K = 3.050\times 10^{8}M^{-1}s^{-1}

K_{278K} = equilibrium constant at 278 K = 3.600\times 10^{7}M^{-1}s^{-1}

E_a = Activation energy = ?

R = Gas constant = 8.314 J/mol K

T_1 = initial temperature = 278 K

T_2 = final temperature = 317 K

Putting values in above equation, we get:

\ln(\frac{3.050\times 10^8}{3.600\times 10^{7}})=\frac{E_a}{8.314J/mol.K}[\frac{1}{278}-\frac{1}{317}]\\\\E_a=40143.3J/mol=40.143kJ/mol

Hence, the activation energy for the reaction is 40.143 kJ/mol

8 0
3 years ago
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