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Nastasia [14]
4 years ago
9

In a certain city, electricity costs $ 0.18 per kW ⋅ h . What is the annual cost for electricity to power a lamppost for 5.00 h

per day with a 100. W incandescent light bulb versus an energy efficient 25 W fluorescent bulb that produces the same amount of light? Assume 1 year = 365 days .
Chemistry
1 answer:
LuckyWell [14K]4 years ago
6 0

Answer:

The cost of electricity  for 100 W power bulb = $ 32.85

Cost of electricity for 0.025 W  fluorescent  bulb =  $ 8.2125

Explanation:

Cost of electricity = $ 0.18 per KW-H

Time = 5 hour per day

Bulb power = 100 W = 0.1 KW

Fluorescent bulb power = 25 W = 0.025 KW

(a) Cost of electricity for 100 W power bulb

0.1 × 5 × 365 × 0.18 =  $ 32.85

(b) Cost of electricity for 0.025 W  fluorescent  bulb

0.025 × 5 × 365 × 0.18 = $ 8.2125

Therefore the cost of electricity  for 100 W power bulb = $ 32.85

Cost of electricity for 0.025 W  fluorescent  bulb =  $ 8.2125

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Answer:

(a) 0.294 mol silver = 1.770 * 10^{23}  

(b) 8.98 * 10-3 mol sodium chloride - 5.407 *10^{23}  

(c) 23.3 mol carbon dioxide  = 1.403 * 10^{25}

(d) 0.310 mol nitrogen (N2) = 1.866 * 10^{23}

Explanation:

In one mole there are 6.022 * 10^{23} atoms/molecules

(a) 0.294 mol silver = 6.022 * 10^{23} * 0.294 = 1.770 * 10^{23}  

(b) 8.98 * 10-3 mol sodium chloride - 5.407 *10^{23}  

(c) 23.3 mol carbon dioxide  = 23.3 * 6.022 * 10^{23} = 1.403 * 10^{25}

(d) 0.310 mol nitrogen (N2) = 0.310 * 6.022 * 10^{23} = 1.866 * 10^{23}

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Answer:

a > c > b

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