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vredina [299]
3 years ago
6

Algebra help. Zoom in if you can

Mathematics
1 answer:
Artist 52 [7]3 years ago
7 0
Answers:

Pair-1: log_{2}x = 5 ↔ 32
Pair-2: log_{10}x = 3 ↔ 1000
Pair-3: log_{4}x = 2 ↔ 16
Pair-4: log_{5}x = 4 ↔ 625

Explanation:

Pair-1:
log_{2}x = 5 \\  \frac{ln(x)}{ln(2)} = 5 \\ ln(x) = 5 * ln(2) \\ x = e^{5*ln(2)} \\ x = 32

Pair-2:
log_{10}x = 3 \\ \frac{ln(x)}{ln(10)} = 3 \\ ln(x) = 3 * ln(10) \\ x = e^{3*ln(10)} \\ x = 1000

Pair-3:
log_{4}x = 2 \\ \frac{ln(x)}{ln(4)} = 2 \\ ln(x) = 2 * ln(4) \\ x = e^{2*ln(4)} \\ x = 16

Pair-4:
log_{5}x = 4 \\ \frac{ln(x)}{ln(5)} = 4 \\ ln(x) = 4 * ln(5) \\ x = e^{4*ln(5)} \\ x = 625
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SVEN [57.7K]

Answer:

x= 35 gallons consumed by 1st car

and y= 40  gallons consumed by 2nd car

Step-by-step explanation:

Fuel efficiency of 1st car = 15 miles per gallon

Fuel efficiency of 2nd car = 35 miles per gallon

Let x= gallons consumed by 1st car

and y= gallons consumed by 2nd car

Total gallons consumed by both cars = 75

so, we can write

x + y = 75

Miles covered by both cars = 1925 miles

and we know, Fuel efficiency of 1st car = 15 miles per gallon

Fuel efficiency of 2nd car = 35 miles per gallon

we can write the equation as

15 x + 35 y = 1925

where x and y are gallons consumed by 1st and 2nd car.

We have two equation now,

x + y = 75                   (1)

15 x + 35 y = 1925     (2)

Multiplying eq(1) with 15 and subtracting eq (1) and 2

15 x + 15 y = 1125

15 x + 35 y = 1925

-       -            -

_______________

0 - 20 y = -800

y= -800 / -20

y = 40

Putting value of y in equation 1

x + y = 75

x + 40 = 75

x= 75 - 40

x = 35

x= 35 gallons consumed by 1st car

and y= 40  gallons consumed by 2nd car

4 0
3 years ago
What is he value of F(-3)
PolarNik [594]

The correct answer is: " 10 " .

___________________________________________

→ " f(-3) = 10 " .

___________________________________________

Explanation:

___________________________________________


Given:

___________________________________________


f(x) = 7 − x ; if: x ≤ -3 ;


f(x) = x + 4 ; if: x > -3 ;

_________________________________________


Find: " f(-3) " :

_________________________________________


Note:  " f(x) = f(-3) " ;  → " x = - 3 " ;


Since  " x  = -  =3 " ;   →  x is NOT greater than "-3" ;


→ So; " f(x) does NOT equal " x + 4" ;

_________________________________________

Consider our other option given:


We have "x = -3 " .


We our given: If " x ≤ -3 " ; {that is; if "x" is less than or equal to "-3" };


→  then: " f(x) =  7 −  x " .

______________________________________________


Since: " x = - 3 " ;


→ then " x ≤ -3 " ;  and:


→ f(x) = 7 − x  ;


THEN:


→ f(-3) = 7 − (-3) ;  →  Note:  Plug in "-3" for the value(s) of "x" in the equation;

and solve:

→         =  7  +  3 ;    

             =  10 .

___________________________________________________

→  f(-3)  =  10  .


_____________________________________

The answer is:  " 10 " .

_____________________________________

Hope this answer — and explanation — is helpful to you.

Best wishes in your academic pursuits!

_____________________________________

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Answer:

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Step-by-step explanation:

Given:

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Change in percent

Computation:

Change in percent = [(Score in second game - Score in first game)/Score in first game]100

Change in percent = [(58-37)/37]100

Change in percent = [(21)/37]100

Change in percent = 56.75 (Approx.)

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