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kodGreya [7K]
4 years ago
7

What happens to a higher concentration of dissolved molecules on one side of a cell membrane during the process of diffusion?

Physics
1 answer:
MariettaO [177]4 years ago
5 0

Answer:

They move to an area where they are less concentrated

Explanation:

In a cell the surface that separates the system from the surrounding environment is the cell membrane and the exchange of substances between the cell and the medium must occur through this membrane. This exchange is essential to maintain the integrity of the cell and to provide the different chemical species necessary for the metabolic processes that occur permanently within it. As we saw, substances move driven by their gradient of chemical or electrochemical potential. Every substance is formed by molecules that have a certain amount of thermal energy that is indicative of their spontaneous movements, a result of thermal movement is diffusion. A large part of the passage of molecules through the cell membrane is produced by simple diffusion. When one molecule is more concentrated on one side of the membrane than on the other and the membrane is permeable to it, there is a tendency for the molecule to diffuse through the membrane in favor of its concentration gradient. This dezplacement occurs without external energy expenditure (passive transport).

An important example is the oxygen uptake of a cell by performing cellular respiration. Dissolved oxygen diffuses into the cell through the cell membrane. As cellular respiration consumes the entering O2, diffusion within the cell will continue because the concentration gradient favors movement in that direction. The same happens, but in the opposite direction, with carbon dioxide. Then you can see the process in the following animation.

In simple diffusion through a biological membrane, small non-polar solute molecules (no charge) move directly through the membrane in favor of their concentration gradient. Oxygen and carbon dioxide can diffuse rapidly through the membrane. The simple diffusion rate is directly related to the solute concentration; The more concentrated the solute, the faster the diffusion.

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lina2011 [118]

Answer:

375 hz

Explanation:

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5 0
3 years ago
What kind of gas cloud is most likely to give birth to stars? what kind of gas cloud is most likely to give birth to stars? a co
navik [9.2K]
Hello! 

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Have a nice day!
7 0
3 years ago
Please help with these questions as well! I need urgent help! I will give brainliest! God bless!
Radda [10]

6.  Since we are not sure if the person in the question is actively lifting the crate, we have to determine the downwards force of the crate due to gravity and compare it to the normal force.  

F = ma

F = (15.3)(-9.8)

F = -150N

Since the downwards force of the crate is equivalent to the normal force, it means the person is applying no force in picking up the object.  So to pick up a 150N object from scratch, you would have to exert more force than the weight of the object, so the answer is 294N.


7.  Same idea as question 2.  

First determine the weight of the object:

F = ma

F = (30)(-9.8)

F = -294N

The crate in question is not moving, so the magnitudes of the forces in the upwards and downwards direction has to equal to 0.

-294 + 150N + x = 0

x = 144N  

So the person is exerting 144 N.


10.  First find the force of block B to the right due to its acceleration:

F = ma

F = (24)(0.5)

F = 12N

So block B is moving 12N to the right relative to block A due to block A's movement to the left.  However, block A is being applied a much greater force and is moving quicker to the left than block B is moving to the right of bock A.  The force that is causing block B to experience the lower relative force to the right is because of the friction.  To find the friction:

The sum of the forces in the leftward and rightward direction for block B must equal 12N.

75 - x = 12

x = 63N

So the force of friction of block A on block B is 63N to the left.


5 0
3 years ago
A boy pulls a 28.0-kg box with a 230-N force at 35° above a horizontal surface. If the coefficient of kinetic friction between t
ddd [48]

Answer:

1977.696 J

Explanation:

Given;

Weight of the box = 28.0 kg

Force applied by the boy = 230 N

angle between the horizontal and the force = 35°

Therefore,

the horizontal component of the force = 230 × cosθ

= 230 × cos 35°

= 188.405 N

Coefficient of kinetic friction, μ = 0.24

Force by friction, f = μN

here,

N = Normal force = Mass × acceleration due to gravity

or

N = 28 × 9.81 = 274.68 N

therefore,

f = 0.24 × 274.68

or

f = 65.9232 N

Now,

work done by the boy, W₁ = 188.405 N × Displacement  

= 188.405 N × 30

= 5652.15 J

and,

the

work done by the friction, W₂ = - 65.9232 N × Displacement  

= - 65.9232 N × 30 m

= - 1977.696 J

[ since the friction force acts opposite to the direction of motion, therefore the workdone will be negative]

8 0
3 years ago
What characteristics determined the classification of an organism in kingdoms?
sdas [7]
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5 0
3 years ago
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