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madreJ [45]
2 years ago
8

Light does not pass through some materials. What do you think happens

Physics
1 answer:
Hatshy [7]2 years ago
7 0

Answer:

When an electron is hit by a photon of light, it absorbs the quanta of energy the photon was carrying and moves to a higher energy state. One way of thinking about this higher energy state is to imagine that the electron is now moving faster, (it has just been "hit" by a rapidly moving photon)

A photon is a quantum of EM radiation. Its energy is given by E = hf and is related to the frequency f and wavelength λ of the radiation by. E=hf=hcλ(energy of a photon) E = h f = h c λ (energy of a photon) , where E is the energy of a single photon and c is the speed of light.

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How do you find the atomic number of a atom?
Vlada [557]

Answer:  To find the atomic mass of an atom of an element, add up the mass of protons and neutrons.

Explanation: Find the atomic mass of an isotope of carbon that has 7 neutrons. You can see from the periodic table that carbon has an atomic number of 6, which is its number of protons.

6 0
3 years ago
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Suppose that the speed of yellow visible light in a certain transparent medium is 2.01* 105 km/s. What, approximately, is the in
True [87]

Answer:

1.50

Explanation:

Index of refraction:

n=\frac{c}{v} where n is the refractive index, c is the speed of light in vacuum and v is the speed of light in medium.

The speed of light in vacuum is 3.00 \times 10^5 \text{km/s}

Speed of light in medium is 2.01 \times 10^5 \text{km/s}

Thus,

n=\frac{3.00\times 10^5}{2.01\times 10^5}

n=1.50

Index of refraction of this substance through yellow light is 1.50

4 0
3 years ago
A car advertisement states that a certain car can accelerate from rest to
Evgen [1.6K]

Answer:

8 km/h²

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a = v-u/t

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5 0
3 years ago
A bicycle travels 6.10 km due east in 0.210 h, then 11.30 km at 15.0° east of north in 0.560 h, and finally another 6.10 km due
Virty [35]

Answer:

Explanation:

Given

First bicycle travels 6.10 km due to east in 0.21 h

Suppose its position vector is r_1

r_1=6.10\hat{i}

After that it travels 11.30 km at 15^{\circ} east of north  in 0.560 h

suppose its position vector is r_2

r_{2}=11.30\left ( cos15\hat{j}+sin15\hat{i}\right )

after that he finally travel 6.10 km due to east in 0.21 h

suppose its position vector is r_3

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so position of final position is given by

r=r_1+r_{2}+r_{3}

\vec{r}=15.12\hat{i}+10.91\hat{j}

\vec{v_{avg}}=\frac{\vec{r}}{t}

t=0.21+0.56+0.21=0.98 h

\vec{v_{avg}}=15.42\hat{i}+11.13\hat{j}

|v_{avg}|=\sqrt{361.71}=19.01 km/hr

For direction

tan\theta =\frac{11.13}{15.42}=0.721

\theta =35.791^{\circ} w.r.t to x axis

5 0
4 years ago
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4 years ago
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