Would an opah be better suited to live in cold water or warm water? explain
1 answer:
You might be interested in
The correct answer is
<span>C) either the pressure of the gas, the volume of the gas, or both, will increase.
In fact, the ideal gas law can be written as
</span>
<span>where
p is the gas pressure
V is its volume
n is the number of moles
R is the gas constant
T is the absolute temperature of the gas
We can see that if the temperature T increases, then the term on the right in the equation increases, therefore the term on the left should increase as well. In order for this to be possible, at least one between p and V should increase, or also both of them. Therefore, the correct answer is C.</span>
<span>C) either the pressure of the gas, the volume of the gas, or both, will increase.
In fact, the ideal gas law can be written as
</span>
<span>where
p is the gas pressure
V is its volume
n is the number of moles
R is the gas constant
T is the absolute temperature of the gas
We can see that if the temperature T increases, then the term on the right in the equation increases, therefore the term on the left should increase as well. In order for this to be possible, at least one between p and V should increase, or also both of them. Therefore, the correct answer is C.</span>
Answer:
The total electric potential at mid way due to 'q' is
The net Electric field at midway due to 'q' is 0.
Solution:
According to the question, the separation between two parallel plates, plate A and plate B (say) = d
The electric potential at a distance d due to 'Q' is:
Now, for the Electric potential for the two plates A and B at midway between the plates due to 'q':
For plate A,
Similar is the case with plate B:
Since the electric potential is a scalar quantity, the net or total potential is given as the sum of the potential for the two plates:
Now,
The Electric field due to charge Q at a distance is given by:
Now, if the charge q is mid way between the field, then distance is .
Electric Field at plate A, at midway due to charge q:
Similarly, for plate B:
Both the fields for plate A and B are due to charge 'q' and as such will be equal in magnitude with direction of fields opposite to each other and hence cancels out making net Electric field zero.