The term "unbalanced force" in Newton's first law refers to a force that is not entirely counterbalanced (or cancelled) by the other independent forces. Basically, magnitude can be thought of as simply the "value" or "amount" of any physical quantity. It is a scalar quantity at all times.
Force has both a magnitude and a direction because it is a vector quantity. The amount that encapsulates the force's strength is known as its magnitude.
Consider the following scenario: the force is 10 N in the east. The direction is indicated by "towards east," while the force is indicated by "10."
Unless acted upon by an unbalanced force, an object at rest tends to stay at rest, and an object in motion tends to stay in motion with the same speed and direction.
The term "unbalanced force" in Newton's first law refers to a force that is not entirely counterbalanced (or cancelled) by the other independent forces. An uneven force exists if either all the vertical forces (up and down) or all the horizontal forces do not cancel each other. Looking at the free-body diagram for a particular situation makes it easy to recognize whether an unbalanced force is present.
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Answer:
The magnitude and direction of the resultant force are approximately 599.923 newtons and 36.405°.
Explanation:
First, we must calculate the resultant force (
), in newtons, by vectorial sum:
![\vec F = [(-200\,N)\cdot \cos 60^{\circ}+(400\,N)\cdot \cos 45^{\circ}+300\,N]\,\hat{i} + [(200\,N)\cdot \sin 60^{\circ} + (400\,N)\cdot \sin 45^{\circ}-100\,N]\,\hat{j}](https://tex.z-dn.net/?f=%5Cvec%20F%20%3D%20%5B%28-200%5C%2CN%29%5Ccdot%20%5Ccos%2060%5E%7B%5Ccirc%7D%2B%28400%5C%2CN%29%5Ccdot%20%5Ccos%2045%5E%7B%5Ccirc%7D%2B300%5C%2CN%5D%5C%2C%5Chat%7Bi%7D%20%2B%20%5B%28200%5C%2CN%29%5Ccdot%20%5Csin%2060%5E%7B%5Ccirc%7D%20%2B%20%28400%5C%2CN%29%5Ccdot%20%5Csin%2045%5E%7B%5Ccirc%7D-100%5C%2CN%5D%5C%2C%5Chat%7Bj%7D)
(1)
Second, we calculate the magnitude of the resultant force by Pythagorean Theorem:
Let suppose that direction of the resultant force is an standard angle. According to (1), the resultant force is set in the first quadrant:
Where 
is the direction of the resultant force, in sexagesimal degrees.
The magnitude and direction of the resultant force are approximately 599.923 newtons and 36.405°.
Answer:
200metters
Explanation:
because in one second hes going 10 metter in 20 second he will go 20×10=200
A large force is required to accelerate the mass of the bicycle and rider. Once the desired constant velocity is reached, a much smaller force is sufficient to overcome the ever-present frictional forces.
