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noname [10]
3 years ago
7

Jerome is learning how the model of the atom has changed over time as new evidence was gathered. He has images of four models of

the atom, but they are not in the correct order.
An image at left labeled W with overlapping red and blue balls in the center with a circular fuzzy green cloud outside them. An image at center left labeled X with a purple ball in the center surrounded by overlapping concentric black ovals, each with a small green ball on each of the 6 ovals. An image at center right labeled Y with a large black cross in a purple circle with a black line around the purple, with 10 small green balls dispersed within the purple circle. An image at right labeled Z with a purple center outlined in black with two concentric black circles around the center, the inner circle having 2 small green balls on it and the outer circle having 8 small green balls on it.

In what order should Jerome put these models to show the development from the earliest model of the atom to the most recent one?

Y, X, Z, W
Y, Z, W, X
W, Z, X, Y
W, Y, Z, X
Physics
2 answers:
adoni [48]3 years ago
6 0

Answer:

the answer is A. Y, X, Z, W

Explanation:

Stolb23 [73]3 years ago
5 0

Answer:

Y, X, Z, W

Explanation:

You know W is the most recent because it features the nucleus in the middle and the electron cloud which was shown in models after the others.

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V125BC [204]

Answer:

The peak emf of the generator is 40.94 V.

Explanation:

Given that,

Number of turns in primary coil= 11

Number of turns in secondary coil= 18

Peak voltage = 67 V

We nee to calculate the peak emf

Using relation of number of turns and emf

\dfrac{N_{1}}{N_{2}}=\dfrac{E_{1}}{E_{2}}

E_{1}=\dfrac{N_{1}}{N_{2}}\times E_{2}

Where, N₁ = Number of turns in primary coil

N₂ = Number of turns in secondary coil

E₂ = emf across secondary coil

Put the value into the formula

E_{1}=\dfrac{11}{18}\times67

E_{1}=40.94\ V

Hence, The peak emf of the generator is 40.94 V.

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The average specific heat of the human body is 3.6 kJ/kg·°C. If the body temperature of a(n) 96-kg man rises from 37°C to 39°C d
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Answer:

691200 J

Explanation:

From specific heat capacity,

ΔQ = cmΔt.................. Equation 1

Where ΔQ = increase in thermal energy, c = specific heat capacity of the body, m = mass of the man, Δt = rise in temperature.

Given: c = 3.6 kJ/kg.°C = 3600 J/kg.°C, m = 96 kg, Δt = 39-37 = 2 °C.

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