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4 years ago

What is an ore? an object that has been recycled

Physics

1 answer:

motikmotik4 years ago

6 0

an ore is a naturally occurring solid material from which a metal or valuable mineral can be profitably extracted.

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The position of an object is given by the equation x = 4.0t2 - 2.0 t - 4.5where x is in meters and t is in seconds. What is the

s344n2d4d5 [400]

Answer:

Explanation:

x = 4 t^2 - 2 t - 4.5

Position at t = 3 s

x = 4 (3)^2 - 2 (3) - 4.5 = 25.5 m

Velocity at t = 3 s

v = dx / dt = 8 t - 2

v ( t = 3 s) = 8 x 3 - 2 = 22 m/s

Acceleration at t = 3 s

a = dv / dt = 8

a ( t = 3 s ) = 8 m/s^2

When is the velocity = 0

v = 0

8 t - 2 = 0

t = 0.25 second

When is the position = 0

x = 0

4 t^2 - 2 t - 4.5 = 0

$t = \frac{2 \pm \sqrt{4 + 72}}{8}$

t = 1.4 second

8 0

3 years ago

The mass of a glass beaker is known to be 24.2 g. Approximately 5 mL of water are added, and the mass of the beaker and water is

Kamila [148]

Answer: 2 significant figures in 6.4

Explanation:

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

Rules for significant figures:

Digits from 1 to 9 are always significant and have infinite number of significant figures.

All non-zero numbers are always significant. For example: 654, 6.54 and 65.4 all have three significant figures.

All zero’s between integers are always significant. For example: 5005, 5.005 and 50.05 all have four significant figures.

All zero’s preceding the first integers are never significant. For example: 0.0078 has two significant figures.

All zero’s after the decimal point are always significant. For example: 4.500, 45.00 and 450.0 all have four significant figures.

Mass of beaker = 24.2 g

Mass of beaker + mass of water = 30.625 g

Mass of water = 30.625 - Mass of beaker = 30.625 - 24.2 = 6.4g

The rule apply for the addition and subtraction is :

The answer would contain same number of decimal places as there are in the least precise number present.

Thus there are 2 significant figures in mass of water which is 6.4 grams.

7 0

3 years ago

As an example, a 4.00-kg aluminum ball has an apparent mass of 2.10 kg when submerged in a particular liquid: calculate the dens

azamat

Answer:

1.2825 * 10^3 kg/m³

Explanation:

Given that :

Mass of aluminum ball (m1) = 4kg

Apparent mass of ball (m2) = 2.10 kg

Density of aluminum (d1) = 2.7 * 10^3 kg/m³

Density of liquid (d2) =?

Using the relation :

d1 / d2 = m1 / (m2 - m1)

(2.7 * 10^3) / d2 = 4 / (4 - 2.10)

2700 / d2 = 4 / 1.9

4 * d2 = 2700 * 1.9

4 * d2 = 5130

d2 = 5130 / 4

d2 = 1282.5 kg/m³

Hence, density of liquid = 1.2825 * 10^3

6 0

3 years ago

Consecutive resonances occur at wavelengths of 8 m and 4.8 m in an organ pipe closed at one end. What is the length of the organ

pashok25 [27]

Answer:

Length of the organ pipe is 6 meters.

Explanation:

Let resonance occur at wavelengths of 8 m at n and wavelength of 4.8 m at (n+2). We know that resonance occurs at,

$L=n\dfrac{\lambda}{4}$

$L=n\dfrac{8}{4}$

L = 2 n.................(1)

And,

$L=(n+2)\dfrac{4.8}{4}$

$L=n\dfrac{8}{4}$

$2n=1.2n+2.4$ (from equation (1))

n = 3

Put the value of n in equation (1). So,

$L=2\times 3=6\ m$

So, the length of the organ pipe is 6 meters. Hence, this is the required solution.

8 0

4 years ago

Read 2 more answers

You are standing on a sheet of ice that covers the football stadium parking lot in Buffalo; there is negligible friction between

Fudgin [204]

Answer:

$(a)\;V=0.058\;m/s\\(b)\;v_{2f}=0.1002\;m/s$

Explanation:

Given,

Mass of ball $m_{1}=0.4$ kg

Speed of ball $v_{1i}=11$ m/s

Mass of persona $m_{2}=75$ kg

(a) The person is at rest initially. So, by the conservation of momentum

$p_{i}=p_{f}\\m_{1}v{1i}+m_{2}v_{2i}=(m_{1}+m_{2})V\\0.4\times 11+75 \times0=(0.4+75)V\\V=0.058\;m/s$

(b) Final speed of ball $v_{1f}=-7.8\;m/s$

$p_{i}=p_{f}\\m_{1}v{1i}+m_{2}v_{2i}=m_{1}v{1f}+m_{2}v_{2f}\\0.4\times 11+75 \times0=0.4\times(-7.8)+75v_{2f}\\v_{2f}=0.1002\;m/s$

3 0

4 years ago

Read 2 more answers