Given,
The initial inside diameter of the pipe, d₁=4.50 cm=0.045 m
The initial speed of the water, v₁=12.5 m/s
The diameter of the pipe at a later position, d₂=6.25 cm=0.065 m
From the continuity equation,
Where A₁ is the area of the cross-section at the initial position, A₂ is the area of the cross-section of the pipe at a later position, and v₂ is the flow rate of the water at the later position.
On substituting the known values,
Thus, the flow rate of the water at the later position is 5.99 m/s
Answer:
a. one line down one line to the right one live to the northwest from the object
b. t1=190 t2=310
Explanation:
Answer:
Part i)
h = 5.44 m
Part ii)
h = 3.16 m
Explanation:
Part i)
Since the ball is rolling so its total kinetic energy in this case will convert into gravitational potential energy
So we have
here we know that for spherical shell and pure rolling conditions
Part b)
If ball is not rolling and just sliding over the hill then in that case
"These deep-ocean currents are driven by differences in the water's density, which is controlled by temperature (thermo) and salinity (haline). This process is known as thermohaline circulation. In the Earth's polar regions ocean watergets very cold, forming sea ice." this is what I found...
Explanation:
the inability to change the position from rest to motion or motion to rest by themselves is inertia.
