Explanation:
Given that,
Initial speed of the airfield, u = 0
Final speed, v = 27.8 m/s
Acceleration of the airfield, 
Length of the runway, d = 150 m
Let v' is the speed of the airplane to reach the required speed for takeoff. Finding v' using third equation of motion as :
This speed is not enough as the airfield must reach a speed before takeoff of at least 27.8 m/s. Now, the required length of the runways is :
So, the minimum length of the runways is 193.21 meters.
Answer:
one at the edge
Explanation:
The relation between the linear velocity and the angular velocity is given by
v = r x ω
Where, v be the linear velocity, ω be the angular velocity and r be the radius of the circular path.
As the angular velocity is constant, thus, the linear velocity depends on the radius of circular path.
So, the horse which is near to the edge has maximum radius of circular path in which it is rotating. So, the horse which is at the edge of the merry go round has maximum linear speed.
Answer: C
Reflection
Explanation: Light travels in a straight line. Reflection is one of the properties of light. And this is the property in which mirror make use of. The ability of light to bounce back. It's this bouncing back characteristics of light ray that eventually produce the image of an object by the mirror.
If the light ray is absorbed, no image will be produced.
Answer:
15.8 seconds
Explanation:
Create an extended calculation to convert all the unit to what you need.
160 km 1000 m 1 hour 1 min
----------- x ------------- x -------------- x ---------- = 44.4 m/s
1 hour 1 km 60 min 60 sec
So 160km/hr is equal to 44.4m/s
Now you can figure out how many seconds it will take to go 700 meters.
44.4 m
---------- X x sec = 700 m
1 sec
Solve for x sec
x sec = 700m / 44.4 m/s
= 15.8 seconds
