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PtichkaEL [24]
2 years ago
10

A serving of Cheez-Its releases 1.30 x 10^4 kcal (1 kcal = 4.18 kJ) when digested by your body. If this same amount of energy we

re transferred to 1.75 mg of water at 35˚C, what would the final temperature be?
Chemistry
1 answer:
kondor19780726 [428]2 years ago
3 0

Answer:

The final temperature is:- 7428571463.57 °C

Explanation:

The expression for the calculation of heat is shown below as:-

Q=m\times C\times \Delta T

Where,  

Q  is the heat absorbed/released

m is the mass

C is the specific heat capacity

\Delta T  is the temperature change

Thus, given that:-

Mass of water = 1.75 mg = 0.00175 g ( 1 g = 0.001 mg)

Specific heat of water = 4.18 J/g°C

Initial temperature = 35 °C

Final temperature = x °C

\Delta T=(x-35)\ ^0C/tex]
Q = [tex]1.3\times 10^4 kcal

Also, 1 kcal = 4.18 kJ = 4.18\times 10^3 J

So, Q = 1.3\times 10^4\times 4.18\times 10^3 J = 54340000 J

So,  

54340000=0.00175\times 4.18\times (x-35)

0.00175\times \:4.18\left(x-35\right)=54340000

x-35=\frac{54340000}{0.007315}

x=7428571463.57

Thus, the final temperature is:- 7428571463.57 °C

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