1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
babunello [35]
3 years ago
9

Spheres are not perfect in space. But <> is in the cause of their shape. ​

Physics
1 answer:
MariettaO [177]3 years ago
8 0

Answer:

\boxed {  \tt{gravitational \: pull(force)}}

You might be interested in
What average power must be supplied to the rope to generate sinusoidal waves that have amplitude 0.200 m and wavelength 0.600 m
pychu [463]

Complete question:

A taut rope has a mass of 0.123 kg and a length of 3.54 m. What average power must be supplied to the rope to generate sinusoidal waves that have amplitude 0.200 m and wavelength 0.600 m if the waves are to travel at 28.0 m/s ?

Answer:

The average power supplied to the rope to generate sinusoidal waves is 1676.159 watts.

Explanation:

Velocity = Frequency  X wavelength

V = Fλ ⇒ F = V/λ

F = 28/0.6 = 46.67 Hz

Angular frequency (ω) = 2πF = 2π (46.67) = 93.34π rad/s

Average power supplied to the rope will be calculated as follows

P_{avg} =\frac{1}{2} \mu \omega^2 A^2 V

where;

ω is the angular frequency

A is the amplitude

V is the velocity

μ is mass per unit length = 0.123/3.54 = 0.0348 kg/m

P_{avg} =\frac{1}{2} ( 0.0348)(93.34 \pi )^2 (0.2)^2 (28) = 1676.159 watts

The average power supplied to the rope to generate sinusoidal waves is 1676.159 watts.

6 0
3 years ago
Ms. Mayo challenged her students to build a pendulum that would hit a block of wood and make it travel the farthest distance. Th
cestrela7 [59]

Answer:

<u>B) mass of pendulum bob</u>

4 0
3 years ago
A 2kg book is held against a vertical wall. The coefficient of friction is 0.45. What is the minimum force that must be applied
Vika [28.1K]

We have that for the Question "A 2kg book is held against a vertical wall. The <em>coefficient </em>of friction is 0.45. What is the minimum force that must be applied on the <em>book</em>, perpendicular to the wall, to prevent the book from slipping down the wal" it can be said that  the minimum force that must be applied on the <em>book is</em>

  • F=44N

From the question we are told

A 2kg book is held against a vertical wall. The <em>coefficient </em>of friction is 0.45. What is the minimum force that must be applied on the <em>book</em>, perpendicular to the wall, to prevent the book from slipping down the wal

Generally the equation for the  Force  is mathematically given as

F=\frac{mg}{\mu}\\\\F=\frac{2*9.8}{0.45}\\\\

F=44N

Therefore

the minimum force that must be applied on the <em>book is</em>

F=44N

For more information on this visit

brainly.com/question/23379286

8 0
2 years ago
Why do you like the full moon ?
mr_godi [17]

Answer:

<h3>The Moon brings perspective. Observing the Moon, and I mean really looking – sitting comfortably, or lying down on a patch of grass and letting her light fill your eyes, it's easy to be reminded of how ancient and everlasting the celestial bodies are. When I do this, it always puts my life into perspective.</h3>
4 0
3 years ago
Read 2 more answers
Suppose that a planet were discovered between the sun and Mercury, with a circular orbit of radius equal to 2/3 of the average o
Musya8 [376]

Explanation:

It is given that,

A planet were discovered between the sun and Mercury, with a circular orbit of radius equal to 2/3 of the average orbit radius of Mercury.

Mass of the Sun, M=1.99\times 10^{30}\ kg

Radius of Mercury's orbit, r=5.79\times 10^{10}\ m

Radius of discovered planet, R=\dfrac{2}{3}r

R=\dfrac{2}{3}\times 5.79\times 10^{10}\ m=3.86\times 10^{10}\ m

Let T is the orbital period of such a planet. Using Kepler's third law of planetary motion as :

T^2\propto R^3

T^2=\dfrac{4\pi^2R^3}{GM}

T^2=\dfrac{4\pi^2\times (3.86\times 10^{10})^3}{6.67\times 10^{-11}\times 1.99\times 10^{30}}

T=\sqrt{1.71\times 10^{13}}

T = 4135214.625 s

or

T = 47.86 days

So, the orbital period of such a planet is 47.86 days. Hence, this is the required solution.

6 0
3 years ago
Other questions:
  • To get the whole circle, you run t from 0 to 2 π. Use this information to confirm that the circumference of a circle of radius r
    7·1 answer
  • Ronald wants to see if a new shower cleaner works better in removing soap than his old cleaner.  He uses the new cleaner on one
    8·1 answer
  • When monochromatic light passes through the interface between two unknown materials at an angle θ where 0∘&lt;θ&lt;90∘, no chang
    6·1 answer
  • The number of mushrooms needed by a pizza restaurant is given by the
    12·1 answer
  • Calculate the number of molecules of hydrogen and carbon present in 4 g of methane​
    7·2 answers
  • PLEASE HELPP!!! I NEED ANSWERS!!!
    11·1 answer
  • On what factors do pressure depend ​
    9·1 answer
  • Which forces are contact forces give one example of each​
    15·1 answer
  • The wind blows a lawn chair that weighs 4 kg into a fence with a force of 8 N. How much reaction force does the fence exert on t
    10·1 answer
  • A baseball is thrown horizontally at 55m/s. The ball slows down at a rate of -10 m/s2. How long is the ball in the air before co
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!