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Pani-rosa [81]
3 years ago
15

Hurry I need help quickThe table shows the mass and boiling point of some substances. Boiling Point of Substances Mass (kg) Boil

ing Point of Water (°C) Boiling Point of Soybean Oil (°C) 1 100 N 2 M 300
Part 1: What is the difference between N and M?
Part 2: Explain your answer for Part 1.
Chemistry
2 answers:
Bogdan [553]3 years ago
7 0

<u>Answer:</u> The correct answer is 200°C

<u>Explanation:</u>

Boiling point is defined as the temperature at which liquid state starts to convert into gaseous state. It is an intensive property.

Intensive property is defined as the property which does not depend upon the amount of substance. It remains same.

Extensive property is defined as the property which depends upon the amount of substance. Its value changes as the amount of substance changes.

Boiling point of a substance will not change for given mass of substances.

Boiling point of water = 100°C

Boiling point of soybean oil = 300°C

From the given table:

Value of M = 100°C

Value of N = 300°C

So, the difference in the values of N and M = (300 - 100)°C= 200°C

Hence, the correct answer is 200°C

Talja [164]3 years ago
4 0

I am probably wrong but I would think 900. I wouldn’t submit that without somebody backing me up though.

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Answer:

Explanation:

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Consider the reaction given below.
Drupady [299]

Answer:

  • <u>K =  0.167 s⁻¹</u>

Explanation:

<u>1) Rate law, at a given temperature:</u>

  • Since all the data are obtained at the same temperature, the equilibrium constant is the same.

  • Since only reactants A and B participate in the reaction, you assume that the form of the rate law is:

        r = K [A]ᵃ [B]ᵇ

<u>2) Use the data from the table</u>

  • Since the first and second set of data have the same concentration of the reactant A, you can use them to find the exponent b:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₂ = (1.50)ᵃ (2.50)ᵇ = 2.50 × 10⁻¹ M/s

         Divide r₂ by r₁:     [ 2.50 / 1.50] ᵇ = 1 ⇒ b = 0

  • Use the first and second set of data to find the exponent a:

        r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

        r₃ = (3.00)ᵃ (1.50)ᵇ = 5.00 × 10⁻¹ M/s

        Divide r₃ by r₂: [3.00 / 1.50]ᵃ = [5.00 / 2.50]

                                  2ᵃ = 2 ⇒ a = 1

         

<u>3) Write the rate law</u>

  • r = K [A]¹ [B]⁰ = K[A]

This means, that the rate is independent of reactant B and is of first order respect reactant A.

<u>4) Use any set of data to find K</u>

With the first set of data

  • r = K (1.50 M) = 2.50 × 10⁻¹ M/s ⇒ K = 0.250 M/s / 1.50 M = 0.167 s⁻¹

Result: the rate constant is K =  0.167 s⁻¹

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