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kirill115 [55]
3 years ago
9

_____ contains chemical energy. A. Heat B. Light C. Natural gas

Physics
2 answers:
FinnZ [79.3K]3 years ago
5 0

The answer is C. Natural gas because both A and B are their own forms of energy.

leonid [27]3 years ago
3 0
The answer is C natural gas. Chemical energy is energy stored in bonds of atoms and molecules natural gas is an example of chemical energy.
You might be interested in
Which will reduce the possible environmental damage associated with mining uranium?
nignag [31]

Answer:

B

Explanation:

Edge 2021

6 0
3 years ago
At what temperature will silver have a resistivity that is two times the resistivity of iron at room temperature? (Assume room t
emmasim [6.3K]

Answer:

The temperature of silver at this given resistivity is 2971.1 ⁰C

Explanation:

The resistivity of silver is calculated as follows;

R_t = R_o[1 + \alpha(T-T_o)]\\\\

where;

Rt is the resistivity of silver at the given temperature

Ro is the resistivity of silver at room temperature

α is the temperature coefficient of resistance

To is the room temperature

T is the temperature at which the resistivity of silver will be two times the resistivity of iron at room temperature

R_t = R_o[1 + \alpha(T-T_o)]\\\\\R_t = 1.59*10^{-8}[1 + 0.0038(T-20)]

Resistivity of iron at room temperature = 9.71 x 10⁻⁸ ohm.m

When silver's resistivity becomes 2 times the resistivity of iron, we will have the following equations;

R_t,_{silver} = 2R_o,_{iron}\\\\1.59*10^{-8}[1 + 0.0038(T-20)] =(2 *9.71*10^{-8})\\\\\ \ (divide \ through \ by \ 1.59*10^{-8})\\\\1 + 0.0038(T-20) = 12.214\\\\1 + 0.0038T - 0.076 = 12.214\\\\0.0038T +0.924 = 12.214\\\\0.0038T  = 12.214 - 0.924\\\\0.0038T = 11.29\\\\T = \frac{11.29}{0.0038} \\\\T = 2971.1 \ ^0C

Therefore, the temperature of silver at this given resistivity is 2971.1 ⁰C

8 0
4 years ago
373698 on expanded num
Vladimir79 [104]
300,000+70,000+3,000+600+90+8
5 0
3 years ago
Read 2 more answers
Nguồn phát của tia X
Naya [18.7K]

Answer:

Từ ánh sáng từ mặt trời đến nhiệt liên tục phát ra từ cơ thể chúng ta, có nhiều dạng bức xạ khác nhau. Tuy nhiên, khi nói đến bức xạ và nguy cơ ung thư, hầu hết mọi người đều nghĩ đến tia X và tia gamma.

Các nguồn tự nhiên của tia X và tia gamma bao gồm khí radon, chất phóng xạ trong lòng đất và các tia vũ trụ tấn công hành tinh từ không gian. Tuy nhiên, loại bức xạ này cũng có thể do con người gây ra. Tia X và tia gamma được sản xuất trong các nhà máy điện hạt nhân để sử dụng trong các xét nghiệm hình ảnh y tế, điều trị ung thư, chiếu xạ thực phẩm và máy quét an ninh sân bay với liều lượng nhỏ.

English:

From light from the sun to the heat that is continuously emitted from our bodies, there are many different forms of radiation. However, when it comes to radiation and cancer risk, most people think of X-rays and gamma rays.

Natural sources of X-rays and gamma rays include radon gas, underground radioactive material, and cosmic rays that strike the planet from space. However, this type of radiation can also be caused by humans. X-rays and gamma rays are produced in nuclear power plants for use in medical imaging tests, cancer treatments, food irradiation and airport security scanners in small doses.

7 0
3 years ago
The maximum distance from the Earth to the Sun (at aphelion) is 1.521 1011 m, and the distance of closest approach (at perihelio
LUCKY_DIMON [66]

Answer:

29274.93096 m/s

2.73966\times 10^{33}\ J

-5.39323\times 10^{33}\ J

2.56249\times 10^{33}\ J

-5.21594\times 10^{33}

Explanation:

r_p = Distance at perihelion = 1.471\times 10^{11}\ m

r_a = Distance at aphelion = 1.521\times 10^{11}\ m

v_p = Velocity at perihelion = 3.027\times 10^{4}\ m/s

v_a = Velocity at aphelion

m = Mass of the Earth =  5.98 × 10²⁴ kg

M = Mass of Sun = 1.9889\times 10^{30}\ kg

Here, the angular momentum is conserved

L_p=L_a\\\Rightarrow r_pv_p=r_av_a\\\Rightarrow v_a=\frac{r_pv_p}{r_a}\\\Rightarrow v_a=\frac{1.471\times 10^{11}\times 3.027\times 10^{4}}{1.521\times 10^{11}}\\\Rightarrow v_a=29274.93096\ m/s

Earth's orbital speed at aphelion is 29274.93096 m/s

Kinetic energy is given by

K=\frac{1}{2}mv_p^2\\\Rightarrow K=\frac{1}{2}\times 5.98\times 10^{24}(3.027\times 10^{4})^2\\\Rightarrow K=2.73966\times 10^{33}\ J

Kinetic energy at perihelion is 2.73966\times 10^{33}\ J

Potential energy is given by

P=-\frac{GMm}{r_p}\\\Rightarrow P=-\frac{6.67\times 10^{-11}\times 1.989\times 10^{30}\times 5.98\times 10^{24}}{1.471\times  10^{11}}\\\Rightarrow P=-5.39323\times 10^{33}

Potential energy at perihelion is -5.39323\times 10^{33}\ J

K=\frac{1}{2}mv_a^2\\\Rightarrow K=\frac{1}{2}\times 5.98\times 10^{24}(29274.93096)^2\\\Rightarrow K=2.56249\times 10^{33}\ J

Kinetic energy at aphelion is 2.56249\times 10^{33}\ J

Potential energy is given by

P=-\frac{GMm}{r_a}\\\Rightarrow P=-\frac{6.67\times 10^{-11}\times 1.989\times 10^{30}\times 5.98\times 10^{24}}{1.521\times 10^{11}}\\\Rightarrow P=-5.21594\times 10^{33}

Potential energy at aphelion is -5.21594\times 10^{33}\ J

6 0
3 years ago
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