All categories

2 years ago

galatics years. the time the solar system takes to circle around the center of mily way galaxy a galatic year is about 230

1 answer:

5 0

Based on the time that the solar system takes to circle the center of the milky way, the length of time that the Tyrannosaurus rex dinosaurs lived is 0.291 galactic years ago.

<h3>How long ago did the Tyrannosaurus rex live?</h3>

The Tyrannosaurus rex lived 67 million years ago.

If a single galactic year is 230 million years then the Tyrannosaurus rex lived:

= Number of years ago Tyrannosaurus rex lived / Number of years in galactic years

Solving gives:

= 67 / 230

= 0.291 galactic years ago

Full question is:

Galactic years. The time the Solar System takes to circle around the center of the Milky Way galaxy, a galactic year, is about 230My. In galactic years, how long ago did the Tyrannosaurus rex dinosaurs live?

Find out more on galactic years at brainly.com/question/13600471

#SPJ4

You might be interested in

For a charged hollow metal sphere with total charge Q and radius R centered on the origin: (Determine whether each of the follow

Sloan [31]

Answer:

1. The field inside the shell is 0; TRUE

2. The field for r>R will be the same as a field for the point charge Q, at the origin: TRUE

3. only positive charges can be on the outside surface: FALSE (Negative can too!!!)

4. The field on the outside is perpendicular to the surface: TRUE

Explanation:

5 0

3 years ago

Someone pls help me with this!

Lina20 [59]

Answer:

Explanation:

<u>Coulomb's Law </u>

The electrostatic force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.

Written as a formula:

$\displaystyle F=k\frac{q_1q_2}{d^2}$

Where:

$k=9\cdot 10^9\ N.m^2/c^2$

q1, q2 = the objects' charge in coulomb

d= The distance between the objects in meters

Object 1 has a charge of

$q_1=-2.3\cdot 10^{-6}\ c$

Object 2 has a charge of

$q_2=-4.2\cdot 10^{-6}\ c$

They are separated by a distance of

d = 0.099 m

Calculate the force:

$\displaystyle F=9\cdot 10^9\frac{2.3\cdot 10^{-6}*4.2\cdot 10^{-6}}{0.099^2}$

F=8.87 N

5 0

3 years ago

Which box has a larger upward force (normal force) acting on it?

andrezito [222]

Answer:

Explanation:

I makes the most sense in math. if you put a 3 in the m box it will be the same. So all they did is take out the 3 in the m box

4 0

3 years ago

5. average A body sets off from rest with a constant acceleration of 8.0 m/s? What distance will it have covered after 3.0 s? 6.

chubhunter [2.5K]

Answer:

$\boxed {\boxed {\sf 36 \ meters}}$

Explanation:

We are asked to find the distance a body covers. We know the initial velocity, acceleration, and time, so we will use the following kinematic equation.

$d= v_i t+ \frac {1}{2} \ at^2$