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umka2103 [35]
2 years ago
8

galatics years. the time the solar system takes to circle around the center of mily way galaxy a galatic year is about 230

Physics
1 answer:
IRINA_888 [86]2 years ago
5 0

Based on the time that the solar system takes to circle the center of the milky way, the length of time that the Tyrannosaurus rex dinosaurs lived is  0.291 galactic years ago.

<h3>How long ago did the Tyrannosaurus rex live?</h3>

The Tyrannosaurus rex lived 67 million years ago.

If a single galactic year is 230 million years then the Tyrannosaurus rex lived:

= Number of years ago  Tyrannosaurus rex lived / Number of years in galactic years

Solving gives:

= 67 / 230

= 0.291 galactic years ago

Full question is:

Galactic years. The time the Solar System takes to circle around the center of the Milky Way galaxy, a galactic year, is about 230My. In galactic years, how long ago did the Tyrannosaurus rex dinosaurs live?

Find out more on galactic years at brainly.com/question/13600471

#SPJ4

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Answer:

(a): The resultant force acting on the object are F= (5.99 i + 14.98 j).

(b): The magnitude of the resultant force are F= 16.4 N < 68.19º .

Explanation:

m= 3kg

a= 2 i + 5 j = 5 .38 < 68.19 º

F= m * a

F= 3* ( 5.38 < 68.19º )

F= 16.4 N < 68.19º

Fx= F * cos(68.19º)

Fx= 5.99

Fy= F* sin(68.19º)

Fy= 14.98

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Resisting force is
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D

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A toy cannon launches a 46-g golf ball straight up into the air with a kinetic energy of 6.8 J. What must the
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Answer : The correct option is, (C) 17 m/s

Explanation :

Formula used :

K.E=\frac{1}{2}mv^2

where,

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m = mass of object = 46 g = 0.046 kg    (1 kg = 1000 g)

v = velocity

Now put all the given values in the above formula, we get:

K.E=\frac{1}{2}mv^2

6.8J=\frac{1}{2}\times 0.046kg\times v^2

6.8kg.m^2/s^2=\frac{1}{2}\times 0.046kg\times v^2

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What is a glacier that terminates in the sea
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Given one mole of diamond vs one mole of graphite,
grandymaker [24]

Answer:

The pressure is P= -  6.39*10^8Pa

The temperature is T =1218.63 K

Explanation:

Generally Gibbs free energy is mathematically represented as

                   G = E + PV -TS

   Where  E is the enthalpy

               PV is the pressure volume energy (i.e PV energy)

                S  is the entropy

                T is the temperature

For stability to occur the Gibbs free energy must be equal to zero

Considering Diamond

  So at temperature of  T = 300 K

         E + PV - TS = 0

making P the subject

          P = \frac{TS-E}{V}

Now substituting 300 K for T , 2900 J  for E ,

                              3.42cm^3 = \frac{3.42}{1*10^6} = 3.42*10^{-6}m^3 for V and 2.38 J/K for S

     P = \frac{(300 * 2.38)- 2900}{3.42*10^{-6}}

         P= -  6.39*10^8Pa

The negative sign signifies the direction of the pressure

Given that  P = 1*0^5Pa

making T the subject

            T = \frac{PV+E}{S}

Substituting into the equation

            T = \frac{1*10^5 * 3.42 *10^{-6}+2900}{2.38}

                T =1218.63 K

             

         

7 0
3 years ago
Read 2 more answers
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