Answer:
The net energy is 2.196 eV
Explanation:
Basically, the energy of an atom increases when it absorbs a photon. In addition, the wavelength of the emitted photon is longer such that the atom absorbed a net energy in the process.
Using:
ΔE = h*c*(1/λ - 1/λ
)
where:
ΔE is the net energy in eV (electron-volt). 1 eV is equivalent to 1.602* J.
h = 4.135* eVs
c = 3* m/s
λ = 300 nm = 300*
m
λ = 640 nm = 640*
m
Thus:
ΔE = 4.135* eVs*3*
m/s*(
)
ΔE = 4.135**3*
*1.77*
eV = 2.196 eV
