3H₂ + N₂ → 2NH₃
mole of N₂ = mass ÷ molar mass
= 2.70g ÷ (14 × 2)
= 0.096 mol
mole ratio of N₂ : H₂
1 : 3
∴ if the moles of N₂ = 0.096 mol
then the mole of H₂ = 0.096 mol × 3
= 0.289 mol
Now, mass = mole × molar mass
∴ mass of H₂ needed to react = 0.289 mol × (1 × 2)
= 0.579 g
Answer:
6.00 mol NH₃
Explanation:
N₂ + 3 H₂ ⇆ 2 NH₃
This is the reaction that produces NH₃. Use the mole ratios in the chemical equation to solve. For every 1 mole of N₂ consumed, 2 moles of NH₃ is produced.
(3.00 mol N₂) × (2 mol NH₃/1 mol N₂) = 6.00 mol NH₃
You will produce 6 moles of NH₃.
Answer:
B. hexane
Explanation:
Im not sure I just goggled it
The answer is going to be 1986000. hope that helped
Answer:
1.01 atm
Step-by-step explanation:
To solve this problem, we can use the <em>Combined Gas Laws</em>:
p₁V₁/T₁ = p₂V₂/T₂ Multiply each side by T₂
p₁V₁T₂ = p₂V₂ Divide each side by V₂
p₂ = p₁ × V₁/V₂ × T₂/T₁
Data:
p₁ = 1.05 atm; V₁ = 285 mL; T₁ = 15.8 °C
p₂ = ?; V₂ = 292 mL; T₂ = 11.2 °C
Calculations:
(a) Convert <em>temperatures to kelvins
</em>
T₁ = (15.8+273.15) K = 288.95 K
T₂ = (11.2+273.15) K = 284.35 K
(b) Calculate the <em>pressure
</em>
p₂ = 1.05 atm× (285/292) × (284.35/288.95)
= 1.05 atm × 0.9760 × 0.9840
= 1.01 atm