1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ExtremeBDS [4]
3 years ago
14

6. If it is Tuesday, then Marla tutors chemistry. If Marla tutors chemistry, then she arrives home at 4 P.M.

Mathematics
1 answer:
kkurt [141]3 years ago
4 0
What are you exactly asking here?
You might be interested in
gal created a painting with an area of 56 square inches and a length if 7 inches. they create a second painting with an area of
qwelly [4]

Answer:

5 inches

Step-by-step explanation:

the length of painting is 56/7 = 8in. to find the length of the 2nd painting divide the area by the width: 40/8 = 5

3 0
2 years ago
Simplefly the problem 1/2x/45>61
german

Answer:

x>5490

x

​​ >61

x>61×90

x>5490

8 0
2 years ago
Please help me with these
Alex Ar [27]
When we approach limits, we are finding values that are infinitesimally approaching this x-value. Essentially, we consider the approximate location that this root or limit appears. This is essential when it comes to taking Calculus, and finding the limit or rate of change of a function.

When we are attempting limits questions, there are several tests we attempt first.

1. Evaluate the limit by substituting the value of the x-value as it approaches the value (direct evaluation of a limit)
2. Rearrangement of the function, such that we can evaluate the limit.
3. (TRIGONOMETRIC PROPERTIES)
\lim_{x \to 0} (\frac{sinx}{x}) = 1
\lim_{x \to 0} (\frac{tanx}{x}) = 1
4. Using L'Hopital's Rule for indeterminate limits, such as 0/0, -infinity/infinity, or infinity/infinity.

For example:

1) \lim_{x \to 0}\frac{\sqrt{x} - 5}{x - 25}

We can do this using the first and second method.
<em>Method 1: Direct evaluation:</em>

Substitute x = 0 to the function.
\frac{\sqrt{0} - 5}{0 - 25}
= \frac{-5}{-25}
= \frac{1}{5}

<em>Method 2: Rearranging the function
</em>

We can see that x - 25 can be rewritten as: (√x - 5)(√x + 5)
By rewriting it in this form, the top will cancel with the bottom easily, and our limit comes out the same.

\lim_{x \to 0}\frac{(\sqrt{x} - 5)}{(\sqrt{x} - 5)(\sqrt{x} + 5)}
= \lim_{x \to 0}\frac{1}{(\sqrt{x} + 5)}}
= \frac{1}{5}

Every example works exactly the same way, and by remembering these criteria, every limit question should come out pretty naturally.
8 0
3 years ago
SOMEONE PLEASE HELP ME ASAP PLEASE!!!​
marusya05 [52]

Answer:

5/6 and 6/7

Step-by-step explanation:

In the top of the fraction its going up by one each time (1,2,3,4 so the 5 and 6 would be the top half of the fraction), and in the bottom half its also going up by one but it started at 2 so its one more than the top half  (2,3,4,5, so the 6 and 7 would be the bottom half of the fraction)

4 0
3 years ago
Read 2 more answers
ASAP
Gala2k [10]
35 minutes yes tag it’s let me know if I’m wrong
8 0
3 years ago
Other questions:
  • What is the value of t=1 ∑³ (4 x 1/2^t-1)
    13·1 answer
  • While walking home on a dark night, Joanna saw a bright light in the sky and concluded that it must have been a spaceship from a
    11·2 answers
  • (2a)^4 without exponents
    10·1 answer
  • Integers that are not whole numbers​
    7·2 answers
  • Select all the correct answers. Which statements are correct interpretations of the logarithmic function f(x) = 7 log2 x, with r
    8·1 answer
  • Write each fraction as a decimal. Use bar notation if necessary<br> 3/11
    12·2 answers
  • +
    7·2 answers
  • The product of x and 5
    8·1 answer
  • Erik used the Factor Theorem to find the remainder of 2x3-4x2-28x+6 divided by x+3. If he calculated the remainder to be 0, what
    15·1 answer
  • Can someone simplfy to me why we use different formula in some equations for sin cos tan? Like in some instances we swap variabl
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!