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fomenos
3 years ago
10

Starting at 48th Street, Dylan rides his bike due east on Meridian Road with the wind at his back. He rides for 20 min at 15 mph

. He then stops for 5 min, turns around, and rides back to 48th Street; because of the headwind, his speed is only 10 mph.
Physics
1 answer:
Nezavi [6.7K]3 years ago
6 0

Answer:

55 min

Explanation:

The missing question is: how long does the trip take?

First of all, we need to find the initial distance covered by Dylan. In the first part, he rides for

t_1 = 20 min = \frac{1}{3}h

at a speed of

v = 15 mph

therefore, the distance he covered is

d = v t_1 = (15)(\frac{1}{3})=5 mi

Then Dylan stopped for a time of

t_2 = 5 min = \frac{5}{60}=\frac{1}{12}h

Finally, on the way back, Dylan covered again this distance but travelling at a new speed of

v = 10 mph

So, the time he took is

t_3 = \frac{d}{v}=\frac{5}{10}=\frac{1}{2}h = 30 min

So, the total time of the trip was

t=t_1 + t_2 + t_3 = 20 min + 5 min + 30 min = 55 min

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Answer:

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