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yulyashka [42]
3 years ago
11

Using this formula Vj = V; + at, If a vehicle starts from rest

Physics
1 answer:
Furkat [3]3 years ago
5 0

Answer:

<em>The final speed of the vehicle is 36 m/s</em>

Explanation:

<u>Uniform Acceleration</u>

When an object changes its velocity at the same rate, the acceleration is constant.

The relation between the initial and final speeds is:

v_f=v_o+a.t

Where:

vf  = Final speed

vo = Initial speed

a   = Constant acceleration

t   = Elapsed time

The vehicle starts from rest (vo=0) and accelerates at a=4.5 m/s2 for t=8 seconds. The final speed is:

v_f=0+4.5*8

v_f=36\ m/s

The final speed of the vehicle is 36 m/s

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I think the answer is D

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3 years ago
As a 2.0-kg object moves from (4.4 i + 5j) m to ( 11.6 i - 2j) m, the constant resultant force
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Answer: 107.8\ J

Explanation:

Given

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Force acting (4i-9j)

Work done is given by

\Rightarrow W=F\cdot dx\\\Rightarrow W=(4i-9j)\cdot (11.6i-4.4i-2j-5j)\\\Rightarrow W=(4i-9j)\cdot (7.2i-7j)\\\Rightarrow W=28.8+63\\\Rightarrow W=91.8\ J

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Change in kinetic energy is equal to work done by object

\Rightarrow K_f=K_i+W\\\Rightarrow K_f=16+91.8\\\Rightarrow K_f=107.8\ J

5 0
3 years ago
What process takes solid CO2 from a solid to a gas? A) boiling B) melting C) sublimation D) vaporization
frutty [35]

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<h3>CloutAnswers</h3>
7 0
3 years ago
Read 2 more answers
1. A toy car with mass m1 travels to the right on a frictionless track with a speed of 3 m/s. A second toy car with mass m2 trav
Alika [10]

Answer:

v = 3(m1 - 2m2)/(m1 + m2)

Explanation:

Parameters given:

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Velocity of second toy car with mass m2, u2 = -6 m/s (taking the left direction as the negative x axis)

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v = (3m1 - 6m2) / (m1 + m2)

v = 3(m1 - 2m2) / (m1 + m2)

8 0
3 years ago
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adoni [48]
In finding the distance that covers we simply add the three km which is 
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17 km is the distance they cover.

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3 years ago
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