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Klio2033 [76]
3 years ago
11

The melting point of a substance occurs at the same temperatures as it’s blank point

Physics
2 answers:
azamat3 years ago
4 0

I think it's a.

Explanation:

melting point is boiling

Anna [14]3 years ago
3 0
I agree with them I belive I tea a as well
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Give reasons.<br>a) Sunlight does not fall on the ground where cloud forms shadow.​
Viefleur [7K]

Answer:

Sunlight passing through a cloud is scattered in various directions. Some photons eventually find their way out the bottom of the cloud, some are reflected upwards, and some are absorbed, serving to warm the cloud. Since only a fraction of the light makes it to ground level, you have a shadow.

Explanation:

Hope it helps you

4 0
3 years ago
a convex mirror has a focal length of 0.20 metre calculate the distance of the image of an object placed 0.30 cm from the mirror
anastassius [24]
8 because of the amount of calcium in the equator of the state Minnesota
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2 years ago
When you describe a liquid as thick, are you saying that it has a high or a low viscosity?
Umnica [9.8K]
It is commonly perceived as "thickness", or resistance to pouring. Viscosity describes a fluid's internal resistance to flow and may be thought of as a measure of fluid friction. Thus, water is "thin", having a low viscosity, while vegetable oil is "thick" having a high viscosity.
6 0
2 years ago
5280 feet to meters
lesya [120]

Answer:

1m= 3.2 feets

? = 5280 feets

let ? be n

cross multiply

3.2n = 1×5280

n= 5280÷3.2

n= 1650

so, 5280 feets is equal to 1650 metres

4 0
3 years ago
Una flecha tiene una rapidez de lanzamiento inicial de 18 m/s. Si debe dar en un blanco a 31 m de distancia, que está a la misma
maks197457 [2]

Answer:

34.8 and 55.2º

Explanation:

This is a projectile launching exercise, as we are told that the range of the arrow must be equal to its range and = 31 m let's use the equation

         

The scope equation is

         R = v₀² sin 2θ /g

         sin 2 θ = R g / v₀²

         sin 2 θ = 31 9.8 / 18²

         2 θ = sin⁻¹ 0.93765

          θ = 34.8º

At the launch of projectiles we have two complementary angles with the same range in this case 34.8 and (90-34.8) = 55.2º

4 0
3 years ago
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