By definition of energy efficiency, we derive an expression for the energy rate exhausted to the river ( $Q_{out}$ ), in megawatts:

$Q_{out} = Q_{in} - W$

$Q_{out} = \left(\frac{1}{\eta}-1 \right)\cdot W$ (1)

Where:

$\eta$ - Efficiency.
$W$ - Electric power, in megawatts.

If we know that $\eta = 0.39$ and $W = 330\,MW$ , then the energy rate exhausted to the river is:

$Q_{out} = \left(\frac{1}{0.39}-1 \right)\cdot (330\,MW)$

$Q_{out} = 516.154\,MW$

516.154 megawatts of heat are exhausted to the river that cools the plant.

We kindly to check this question on first law of thermodynamics: brainly.com/question/3808473

7 0

3 years ago

A 150kg person stands on a compression spring with spring constant 10, 000 N/m and norminal.Length of 0.50.What is the togal len

Eva8 [605]

Answer:

Total length of spring 0.647 m

Explanation:

We have given mass of the person m = 150 kg

Acceleration due to gravity $g=9.8m/sec^2$

Spring constant k = 10000 N/m

Nominal length of spring = 0.50

According to hook's law

$mg=kx$

$150\times 9.8=10000\times x$

x = 0.147 m

So total length of spring = 0.50+0.147 = 0.647 m

4 0

3 years ago

When _______ light passes through a prism or diffraction grating

lana66690 [7]

I don’t know ... sorry

5 0

3 years ago

The metric unit of force is the _____. A.newton B.pound C.kilogram D.watt

arsen [322]

A force is calculated in neutons

8 0

3 years ago