Question

From the Bohr equation in the introduction, the calculated energy of an electron in the sixth Bohr orbit of a hydrogen atom is

Answer 1

Answer:

= - 0.38 eV

Explanation:

Using Bohr's equation for the energy of an electron in the nth orbital,

E = -13.6 $\frac{Z^{2} }{n^{2} }$

Where E = energy level in electron volt (eV)

Z = atomic number of atom

n = principal state

Given that n = 6

⇒ E = -13.6 × $\frac{1^{2} }{6^{2} }$

= - 0.38 eV

Hope this was helpful.