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xz_007 [3.2K]
3 years ago
10

From the Bohr equation in the introduction, the calculated energy of an electron in the sixth Bohr orbit of a hydrogen atom is

Chemistry
1 answer:
Natalka [10]3 years ago
4 0

Answer:

<em><u>= - 0.38 eV</u></em>

Explanation:

Using Bohr's equation for the energy of an electron in the nth orbital,

E = -13.6 \frac{Z^{2} }{n^{2} }

Where E = energy level in electron volt (eV)

Z = atomic number of atom

n = principal state

Given that n = 6

⇒ E = -13.6 × \frac{1^{2} }{6^{2} }

<em><u>= - 0.38 eV</u></em>

<em><u></u></em>

<em>Hope this was helpful.</em>

<em><u></u></em>

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2 years ago
2.56 g of hydrogen reacts completely with 20.32 g of oxygen<br> to form X g of water. X = g
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Answer:

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Now we will compare the moles of water with oxygen and hydrogen.

                    O₂            :            H₂O

                     1              :             2

                  0.635        ;            2×0.635 =  1.27

                   H₂             :              H₂O

                    2              :              2

                 1.28            :           1.28

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Mass of water produced:

Mass = number of moles × molar mass

Mass = 1.27 × 18 g/mol

Mass = 22.86 g

 

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3 years ago
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